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jeyben [28]
3 years ago
15

Ind the slope m of the tangent to the curve y = 9 + 4x2 − 2x3 at the point where x =

Mathematics
1 answer:
blagie [28]3 years ago
3 0
Find the derivative:-
y' = 8x - 6x^2
This is the slope in terms of x.
When x = a , the slope is
8a - 6a^2

(b)  equation of tangent line at x1,y1 
is  y- y1  =  (8x - 6x^2)( x - x1) , so at (1,11) it is
y - 11 = (8(1) - 6((1)^2) ) (x - 1)
y =  2(x - 1) + 11
y = 2x + 9 (answer)

At  (2,9) 
y - 9 = (16-24)(x - 2)
y - 9 = -8x + 16
y = -8x + 25  answer

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Which linear inequality is represented by the graph?
Ksju [112]

Tthe inequality that describes this graph is y ≤ 1/3x - 4/3

<h3>How to determine the linear inequality represented by the graph?</h3>

The graph that completes the question is added as an attachment

From the attached graph, we have the following points

(0, -1.3) and (3, -0.3)

The slope is calculated as:

m = (y2 - y1)/(x2 - x1)

Substitute the known values in the above equation

m = (-0.3 + 1.3)/(3 - 0)

Evaluate

m = 1/3

The equation is then calculated as:

y = m(x - x1) + y1

This gives

y = 1/3(x - 0) - 1.3

Evaluate

y = 1/3x - 4/3

From the graph, we have the following highlights:

  • The line of the graph is a closed line
  • The upper part is shaded

The first highlight above implies, the inequality can be any of ≥ and ≤

While the second highlight above implies, the inequality is ≤

Hence, the inequality that describes this graph is y ≤ 1/3x - 4/3

Read more about inequality at

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What is 4/5 multiplied by 10 subtracted by 3 and 1/2?
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