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3 years ago

Simplify the expression below. 7(2x+2)-9(-1+6x)

2 answers:

7 0

Use the distributive property to simplify.

$7(2x+2)-9(-1+6x) \\ 7(2x)+7(2)-9(-1)-9(6x) \\ 14x+14+9-54x$

Group like terms and add/subtract.

$14x-54x+14+9\\\boxed{-40x+23}$

Klio2033 [76]3 years ago

5 0

Distribute 7 and -9.

7(2x + 2) - 9(-1 + 6x)

14x + 14 + 9 - 54x

Combine like terms:

-40x + 23

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"Find the value of X and Y in the parallelogram LMNP.

Leona [35]

For Value of x,

We know, 360 = 2( a+b)

180 = 4x+2x-6

180 = 6x-6

6x = 186

x = 186/6

x = 31

For value of y:

It would be equal,

5y = y+8

5y-y = 8

4y = 8

y = 2

SO, OPTION A IS YOUR ANSWER

4 0

3 years ago

Read 2 more answers

Camille is sixty-six inches tall. This is twenty inches less than two times Mindy's height. How tall is Mindy ?

Shalnov [3]

23 inches

x = Mindy's height
2x - 20 = 66
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7 0

3 years ago

Please find the perimeter and area of these shapes

ladessa [460]

Answer:

ABC shaded area = 36 $\pi$ - 72 cm²

ABC shaded area perimeter = $6\pi +12\sqrt{2}$ cm

ABCD area = $\dfrac52 \pi$ cm²

ABCD perimeter = $3\pi +2$ cm

Step-by-step explanation:

Shape ABC

Assuming you want the area and perimeter of the shaded part of the shape only...

Area

Area of a sector = $\dfrac12r^2\theta$ (where r is the radius and $\theta$

⇒ area of a sector = $\dfrac12 \times 12^2\times \dfrac{\pi}{2} =36\pi \ \textsf{cm}^2$

Area of triangle = 1/2 x base x height

⇒ area of triangle = 1/2 x 12 x 12 = 72 cm²

Therefore, area of shaded area = area of sector - area of triangle

⇒ area = 36 $\pi$ - 72 cm²

Perimeter

Arc length = $r\theta$ (where r is the radius and $\theta$

⇒ arc length = $12\times\dfrac12\pi =6\pi \ \textsf{cm}$

Hypotenuse of triangle = $\sqrt{a^2+b^2}$ (where a and b are the legs of the right triangle)

⇒ hypotenuse = $\sqrt{12^2+12^2} =12\sqrt{2}$ cm

Therefore, perimeter = arc length + hypotenuse

⇒ perimeter = $6\pi +12\sqrt{2}$ cm

Shape ABCD

Area

Area of a semicircle = $\dfrac12 \pi r^2$ (where r is the radius)

⇒ area of large semicircle ABC = $\dfrac12 \times \pi \times 2^2=2\pi \ \textsf{cm}^2$

⇒ area of small semicircle AD = $\dfrac12 \times \pi \times 1^2=\dfrac12\pi \ \textsf{cm}^2$

⇒ area of shape ABCD = $\dfrac12 \pi + 2 \pi=\dfrac52 \pi \ \textsf{cm}^2$

Perimeter

1/2 circumference = $\pi r$

⇒ perimeter = $2\pi +2+\pi=3 \pi+2 \ \textsf{cm}$

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2 years ago

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umka2103 [35]

I think the answer is 8.7332602....I hope I helped!

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4 years ago

Find the measures of the labeled angles

xxTIMURxx [149]

Answer:

4x° = (80 - x)°

Step-by-step explanation:

These angles are known as vertical angles. Vertical angles are equal to one another.

8 0

3 years ago