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denis23 [38]
3 years ago
12

A race car exerts 18,344 N while the car travels at an acceleration of 92.54 m/s2. What is the mass of the car? (Use the formula

m=F/a)
Physics
2 answers:
boyakko [2]3 years ago
7 0

\huge\blue{\tt Given :-}

  • A race car exerts 18,344 N while the car travels at an acceleration of 92.54 m/s²

\huge\orange{\tt To \:  Find :-}

  • Mass of the car

\huge\green{\tt Solution :-}

We have,

  • Force(f) = 18344 N
  • Acceleration(a) = 92.54 m/s²

We know that,

\boxed{\tt m = \frac{f}{a}}

Where,

  • m = Mass
  • f = Force
  • a = Acceleration

Substituting the values we get,

:\implies\tt m = \dfrac{\cancel{18344}}{\cancel{92.54}}

:\implies\tt m ≈ 198.23 \: kg

Therefore, mass of the car is 198.23 kg

Maru [420]3 years ago
4 0

Answer:

<h3>The answer is 198.23 kg</h3>

Explanation:

To find the mass of an object given it's mass and acceleration we use the formula

m =  \frac{f}{a}  \\

where

m is the mass

F is the force

a is the acceleration

From the question

a = 92.54 m/s²

F = 18,344 N

We have

m =  \frac{18344}{92.54}  \\  = 198.2277933...

We have the final answer as

<h3>198.23 kg</h3>

Hope this helps you

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lana66690 [7]

Answer:

Charge on each metal sphere will be 8\times 10^{8}C

Explanation:

We have given number of electron added to metal sphere A n=10^{12}electron

As both the spheres are connected by rod so half -half electron will be distributed on both the spheres.

So electron on both the spheres =\frac{10^{12}}{2}=5\times 10^{11}electron

We know that charge on each electron e=1.6\times 10^{-19}C

So charge on both the spheres will be equal to q=1.6\times 10^{-19}\times 5\times 10^{11}=8\times 10^{8}C

So charge on each metal sphere will be equal to 8\times 10^{8}C

6 0
2 years ago
Ride and average of 15mph for 30 miles, how long does it take?
dalvyx [7]

Answer:

2 hrs

Explanation:

time = distance ÷ speed

3 0
3 years ago
Zero field spot for opposite unequal charges
xz_007 [3.2K]

Answer:

The zero field location has to be on the line running between the two point charges because that's the only place where the field vectors could point in exactly opposite directions. It can't be between the two opposite charges because there the field vectors from both charges point toward the negative charge.

7 0
3 years ago
A piece of string 2 meters and has a mass of 5g. On one end of the string hangs a 200 g mass. Find the tension of the string and
viktelen [127]

Explanation:

It is given that,

Length of the string, l = 2 m

Mass of the string, m=5\ g=5\times 10^{-3}\ kg

Hanged mass in the string, m'=200\ g=0.2\ kg

1. The tension in the string is given by :

T=m'g

T=0.2\times 9.8

T = 1.96 N

2. Velocity of the transverse wave in the string is given by :

v=\sqrt{\dfrac{T}{M}}

m = M/l

v=\sqrt{\dfrac{Tl}{m}}

v=\sqrt{\dfrac{1.96\times 2}{5\times 10^{-3}}}

v = 28 m/s

Hence, this is the required solution.

4 0
3 years ago
A uniform piece of sheet steel is shaped as in the figure below. (Both axes are marked in increments of 2). Compute the x and y
Elena-2011 [213]
"increments of 8" means the major divisions are 0,8,16,24 ? 

<span>x axis, calculate the moment arms from 0 </span>
<span>3x4, 2x12, 1x20 </span>
<span>from an arbitrary C </span>
<span>3(c-4) + 2(c-12) + (c-20) = 0 </span>
<span>3c - 12 + 2c -24 + c - 20 = 0 </span>
<span>6c = 56 </span>
<span>c = 9.33 </span>

<span>y axis </span>
<span>3x3, 1x12, 2x20 </span>
<span>3(c-4) + 1(c-12) +2 (c-20) = 0 </span>
<span>3c - 12 + c - 12 + 2c - 40 = 0 </span>
<span>6c = 64 </span>
<span>c = 10.67 </span>

<span>so center is x = 9.33, y = 10.67 </span>
5 0
3 years ago
Read 2 more answers
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