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ANTONII [103]
3 years ago
10

Speed is velocity in a given direction O True O False

Physics
2 answers:
Zarrin [17]3 years ago
8 0

Answer:

FALSE

Explanation:

Velocity = speed with direction.

Think of speed and direction like rockets and missiles. Rockets are not smart. Missiles are smart. Rockets go in one direction. Missiles can track their targets, they have a specific destination, a specific direction.

Velocity is often used in physics, because its almost useless to know how fast an object is going if you don't know which direction it is going.

Think of it like this. If the Weather man told you a hurricane was traveling at 30 miles an hour, but didn't tell you which direction it was going, you would have no idea where to run, or if it was going to hit you at all. However, if he told you it was going 30 miles an hour to the North, and you were West of it, you would be fine, and wouldn't have to worry.

irinina [24]3 years ago
5 0
False. speed equals velocity
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3 years ago
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Steam at 0.6 MPa, 200 oC, enters an insulated nozzle with a velocity of 50 m/s. It leaves at a pressure of 0.15 MPa and a veloci
Rudiy27

Answer:

x2 = 0.99

Explanation:

from superheated water table

at pressure p1 = 0.6MPa and temperature 200 degree celcius

h1 = 2850.6 kJ/kg

From energy equation we have following relation

\dot m( h1+\frac{v1^2}{2}+ gz1 )+ Q = \dot m( h2+\frac{v2^2}{2}+ gz1) + W

\dot m( h1+\frac{v1^2}{2}) = \dot m( h2+\frac{v2^2}{2})

h1+\frac{v1^2}{2} = h2+\frac{v2^2}{2}

2850.6 + [\frac{50^2}{2} * \frac{1 kJ/kg}{1000 m^2/S^2}] = h2 +[ \frac{600^2}{2} * \frac{1 kJ/kg}{1000 m^2/S^2}]

h2 = 2671.85 kJ/kg

from superheated water table

at pressure p2 = 0.15MPa

specific enthalpy of fluid hf = 467.13 kJ/kg

enthalpy change hfg = 2226.0 kJ/kg

specific enthalpy of the saturated gas hg = 2693.1 kJ/kg

as it can be seen from above value hf>h2>hg, so phase 2 is two phase region. so we have

quality of steam x2

h2 = hf + x2(hfg)

2671.85 = 467.13 +x2*2226.0

x2 = 0.99

6 0
4 years ago
PLEASE HELP!<br> QUESTION 2A,B and C. PLEASE HELP. 50 points
Greeley [361]

Answer:

first

Explanation:

7 0
4 years ago
A researcher is interested in exploring the effects of exposure to ultraviolet light on people’s emotional state. He divides his
bekas [8.4K]

Answer:

Explanation:

In an experimental research, the control group is the group that serves as the neutral group that is not given any form of treatment and serves as the group in which the experimental groups are firstly compared to. Thus, <u>the control group in the question described is the Third group</u>.

While experimental groups are the groups that receive treatments required to make an inference from the experiment. From this description, <u>it can be deduced that the First and the Second group are the experimental groups.</u>

4 0
3 years ago
What is the approximate de Broglie wavelength of a tennis ball with a mass of 70 g and a velocity of 10 m/s
dybincka [34]

The approximate de Broglie wavelength of a tennis ball is 9.4×10^(-34) m.

What is the de Broglie wavelength:

It is the wavelength that is associated with an object in relation to its momentum and mass is known as de Broglie wavelength.

A particle's de Broglie wavelength is usually inversely proportional to its force.

The formula of de Broglie wavelength:

  • λ = h / ( m*v )

here mass of a tennis ball is given

mass, m=70 g = 0.07 kg

ball is moving with velocity

v = 10 m/s

h is Plank constant,

h=6.63×10^(-34) Js

substituting the values in formula,

λ = 6.63×10^(-34) / ( 0.070*10)

λ = 9.4 ×10^(-34) m

Hence

The approximate de Broglie wavelength of a tennis ball is 9.4×10^(-34) m

Learn more about de Broglie wavelength here:

<u>brainly.com/question/17295250</u>

#SPJ4

3 0
2 years ago
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