Answer:
x2 = 0.99
Explanation:
from superheated water table
at pressure p1 = 0.6MPa and temperature 200 degree celcius
h1 = 2850.6 kJ/kg
From energy equation we have following relation



![2850.6 + [\frac{50^2}{2} * \frac{1 kJ/kg}{1000 m^2/S^2}] = h2 +[ \frac{600^2}{2} * \frac{1 kJ/kg}{1000 m^2/S^2}]](https://tex.z-dn.net/?f=2850.6%20%2B%20%5B%5Cfrac%7B50%5E2%7D%7B2%7D%20%2A%20%5Cfrac%7B1%20kJ%2Fkg%7D%7B1000%20m%5E2%2FS%5E2%7D%5D%20%3D%20h2%20%2B%5B%20%5Cfrac%7B600%5E2%7D%7B2%7D%20%2A%20%5Cfrac%7B1%20kJ%2Fkg%7D%7B1000%20m%5E2%2FS%5E2%7D%5D)
h2 = 2671.85 kJ/kg
from superheated water table
at pressure p2 = 0.15MPa
specific enthalpy of fluid hf = 467.13 kJ/kg
enthalpy change hfg = 2226.0 kJ/kg
specific enthalpy of the saturated gas hg = 2693.1 kJ/kg
as it can be seen from above value hf>h2>hg, so phase 2 is two phase region. so we have
quality of steam x2
h2 = hf + x2(hfg)
2671.85 = 467.13 +x2*2226.0
x2 = 0.99
Answer:
Explanation:
In an experimental research, the control group is the group that serves as the neutral group that is not given any form of treatment and serves as the group in which the experimental groups are firstly compared to. Thus, <u>the control group in the question described is the Third group</u>.
While experimental groups are the groups that receive treatments required to make an inference from the experiment. From this description, <u>it can be deduced that the First and the Second group are the experimental groups.</u>
The approximate de Broglie wavelength of a tennis ball is 9.4×10^(-34) m.
What is the de Broglie wavelength:
It is the wavelength that is associated with an object in relation to its momentum and mass is known as de Broglie wavelength.
A particle's de Broglie wavelength is usually inversely proportional to its force.
The formula of de Broglie wavelength:
here mass of a tennis ball is given
mass, m=70 g = 0.07 kg
ball is moving with velocity
v = 10 m/s
h is Plank constant,
h=6.63×10^(-34) Js
substituting the values in formula,
λ = 6.63×10^(-34) / ( 0.070*10)
λ = 9.4 ×10^(-34) m
Hence
The approximate de Broglie wavelength of a tennis ball is 9.4×10^(-34) m
Learn more about de Broglie wavelength here:
<u>brainly.com/question/17295250</u>
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