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Mashcka [7]
3 years ago
8

Given the mathematical representation of Coulomb’s Law, , where , describe in words the relationship among electric force, charg

e, and distance.
Physics
1 answer:
Svetach [21]3 years ago
5 0

Answer:

F_c = \frac{KQ_1Q_2}{R^2}

Explanation:

Coulomb’s law is given as;

F_c = \frac{KQ_1Q_2}{R^2}

where;

F is the electric force between q₁ and q₂

k is the coulomb’s constant  = 9 x 10⁹ Nm²/C²

r is the distance between the two charges

q₁ and q₂ are the two charges

Therefore, the coulomb’s law is given as F_c = \frac{KQ_1Q_2}{R^2}

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A woman throws a baseball straight up into the air. what is the baseball's acceleration at its highest point?
AleksandrR [38]
After the ball leaves the woman's hand, the only relevant force acting on the ball is the gravity, which produces an acceleration of a=g=9.81 m/s^2 on the baseball, directed downward. 
Gravity acts on the ball for the whole duration of the motion, so the acceleration of the ball is g=9.81 m/s^2 at every point of the motion, and therefore also when the baseball is at its highest point.
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3 years ago
The clouds that occur at the highest altitude are usually
gogolik [260]
The answer is A. Cirrus clouds occur at the highest altitude.
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3 years ago
Read 2 more answers
The projectile launcher shown below will give the object on the right an initial horizontal speed of 5.9 m/s. While the other ob
Crazy boy [7]

Answer:

104.3 cm  or 179.7

Explanation:

First find time that it takes for the object to hit the ground

\sqrt{(2H)/g}  ->   \sqrt{(2 x 179)/ 9.8} = 6.04s\\*

Then find xf of projectile xf= 5.9(6.04) = 37.7\\\\

not 100% sure if the projectile is going away from the object or towards it but you either do 142- 37.7   or    142+37.7  

hope that helps

4 0
2 years ago
Which of the following would be the SI unit to use in measuring the temperature of hot liquid
GREYUIT [131]

Answer:

Kelvin

Explanation:

The SI unit to use in measuring the temperature of hot liquid is kelvin (K)

7 0
3 years ago
Consider a motor that exerts a constant torque of 25.0 nâ‹…m to a horizontal platform whose moment of inertia is 50.0 kgâ‹…m2. A
Crazy boy [7]

Answer:

W = 1884J

Explanation:

This question is incomplete. The original question was:

<em>Consider a motor that exerts a constant torque of 25.0 N.m to a horizontal platform whose moment of inertia is 50.0kg.m^2 . Assume that the platform is initially at rest and the torque is applied for 12.0rotations . Neglect friction. </em>

<em> How much work W does the motor do on the platform during this process?  Enter your answer in joules to four significant figures.</em>

The amount of work done by the motor is given by:

W=\Delta K

W= 1/2*I*\omega f^2-1/2*I*\omega o^2

Where I = 50kg.m^2 and ωo = rad/s. We need to calculate ωf.

By using kinematics:

\omega f^2=\omega o^2+2*\alpha*\theta

But we don't have the acceleration yet. So, we have to calculate it by making a sum of torque:

\tau=I*\alpha

\alpha=\tau/I     =>     \alpha = 0.5rad/s^2

Now we can calculate the final velocity:

\omega f = 8.68rad/s

Finally, we calculate the total work:

W= 1/2*I*\omega f^2 = 1883.56J

Since the question asked to "<em>Enter your answer in joules to four significant figures.</em>":

W = 1884J

3 0
3 years ago
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