A box slides down a 30.0° ramp with an acceleration of 1.20 m/s^2. Determine the coefficient of kinetic friction between the box
and the ramp.
1 answer:
m = mass of the box
N = normal force on the box
f = kinetic frictional force on the box
a = acceleration of the box
μ = coefficient of kinetic friction
perpendicular to incline , force equation is given as
N = mg Cos30 eq-1
kinetic frictional force is given as
f = μ N
using eq-1
f = μ mg Cos30
parallel to incline , force equation is given as
mg Sin30 - f = ma
mg Sin30 - μ mg Cos30 = ma
"m" cancel out
a = g Sin30 - μ g Cos30
inserting the values
1.20 = (9.8) Sin30 - (9.8) Cos30 μ
μ = 0.44
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The acceleration of the bus is 1.11 meters per second square to the direction of motion
Explanation:
Acceleration is the rate of change of velocity
The formula of the acceleration is , where
is the initial velocity
is the final velocity
- t is the time
A bus that goes from 10 km/h to a speed of 50 km/h in 10 seconds
→ = 10 km/h
→ = 50 km/h
→ t = 10 seconds
Change the unite of the time from seconds to hour
→ 1 hour = 60 × 60 = 3600 seconds
→ 10 seconds = hour
Substitute these values in the formula of the acceleration above
→
→ a = 14400 km/h²
To change the unit of acceleration to meter per second change the
kilometer to meter and the hour to seconds
→ 1 km = 1000 m
→ 1 hour = 3600 seconds
→
→ a = 1.11 m/sec².
The acceleration of the bus is 1.11 meters per second square to the direction of motion
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Answer: part a: 19.62m
part b: 19.62 m/s
part a: 2.83 secs
Explanation:If the air resistance is ignored then the swimmer experience free fall under gravity hence
u=0
a=9.81 m/s2
t=2 secs
s=h
Part b
Part c
now we have h=2*19.62=39.24