m = mass of the box
N = normal force on the box
f = kinetic frictional force on the box
a = acceleration of the box
μ = coefficient of kinetic friction
perpendicular to incline , force equation is given as
N = mg Cos30 eq-1
kinetic frictional force is given as
f = μ N
using eq-1
f = μ mg Cos30
parallel to incline , force equation is given as
mg Sin30 - f = ma
mg Sin30 - μ mg Cos30 = ma
"m" cancel out
a = g Sin30 - μ g Cos30
inserting the values
1.20 = (9.8) Sin30 - (9.8) Cos30 μ
μ = 0.44
Answer:
Explanation:
The kinetic energy of an object is given by where
is the mass of the object and
is the velocity of the object.
We can set up the following equations with the information given:
For part B, we have the same equation, but kinetic energy is now .
Therefore:
.
Answer:
8.756 rad/s²
Explanation:
Given that:
A motorcycle accelerates uniformly from rest, then initial velocity v_i = 0 m/s
It final velocity v_f = 24.8 m/s
time (t) = 9.87 s
radius (r) of each tire = 0.287 m
Firstly; the linear acceleration of the motor cycle is determined as follows:
=(V_f - v_i)/t
=(24.8-0)/9.87
=2.513 m/s²
Then; the magnitude of angular acceleration
α = /r
=2.513/0.287
=8.756 rad/s²