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labwork [276]
3 years ago
14

When driving in foggy weather driver should not their headlight

Mathematics
2 answers:
olga_2 [115]3 years ago
8 0
Driver should but on headlights and if a car 2016 or newer should have fog lights as well which you should definitely use in foggy conditions
Ahat [919]3 years ago
7 0

Answer:

divers shuld on their head light

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What is the answer to this
Scilla [17]
420, 210, 140, 105, 84, 70, 60, 42, 35, 30, 28, 21, 20, 15, 14, 12, 10, 7, 6, 5, 4, 3, 2, 1
8 0
3 years ago
A cylinder has a base radius of 5 inches and a height of 6 inches. What is its volume in cubic inches, to the nearest tenths pla
yuradex [85]

Answer:

V≈471.24

or to the nearest tenth is

471.2

7 0
3 years ago
Read 2 more answers
Please help me with this.
JulijaS [17]

The <em>speed</em> intervals such that the mileage of the vehicle described is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h]

<h3>How to determine the range of speed associate to desired gas mileages</h3>

In this question we have a <em>quadratic</em> function of the <em>gas</em> mileage (g), in miles per gallon, in terms of the <em>vehicle</em> speed (v), in miles per hour. Based on the information given in the statement we must solve for v the following <em>quadratic</em> function:

g = 10 + 0.7 · v - 0.01 · v²      (1)

An effective approach consists in using a <em>graphing</em> tool, in which a <em>horizontal</em> line (g = 20) is applied on the <em>maximum desired</em> mileage such that we can determine the <em>speed</em> intervals. The <em>speed</em> intervals such that the mileage of the vehicle is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h].

To learn more on quadratic functions: brainly.com/question/5975436

#SPJ1

3 0
2 years ago
Find the number c that satisfies the conclusion of the Mean Value Theorem on the given interval. (Enter your answers as a comma-
Shtirlitz [24]

Answer:

The number c is 2.

Step-by-step explanation:

Mean Value Theorem:

If f is a continuous function in a bounded interval [0,4], there is at least one value of c in (a,b) for which:

f(c) = \frac{1}{b-a}\int\limits^a_b {f(x)} \, dx

In this problem, we have that:

f(x) = x, a = 0, b = 4

So f(c) = c

----------

f(c) = \frac{1}{b-a}\int\limits^a_b {f(x)} \, dx

c = \frac{1}{4-0}\int\limits^0_4 {x} \, dx

c = \frac{1}{4-0}*8

c = 2

The number c is 2.

3 0
3 years ago
What is 2 times 5 to the 3rd power divided by (9-4) raised to the power of 4
Maslowich
Heyo Kiddo. How are you doing today? 

Let's figure this out. 

So in number form, the equation will be looking a little like this: 

2(5) ^{3} / (9-4)^4

To solve. 

2(5) ^{3} / (9-4)^4 \ \textless \ Parenthesis first\ \textgreater \ &#10;&#10;2(5)^{3} / 5^4 \ \textless \ Exponents\ \textgreater \ &#10;&#10;2(125) / 625 (Multiply)&#10;&#10;250 / 625  (Divide)&#10;&#10;0.4  (Answer)

So I hope this answers your question and that you have a great day. :)
8 0
3 years ago
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