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labwork [276]
3 years ago
14

When driving in foggy weather driver should not their headlight

Mathematics
2 answers:
olga_2 [115]3 years ago
8 0
Driver should but on headlights and if a car 2016 or newer should have fog lights as well which you should definitely use in foggy conditions
Ahat [919]3 years ago
7 0

Answer:

divers shuld on their head light

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Write an inequality pls help me on this question!
Helen [10]

Answer:

y = -2x + -3

Step-by-step explanation:

The line has a slope of -2 because when counting from point to point, its 2 down and one over; 2/1 or 2 (negative because the line is going down)

The intercept in -3 because thats the first place the line touches the y axis.

8 0
3 years ago
In the coming year, a vehicle manufacturer has decided to manufacture 150 vehicles per day. The function v = 150d represents the
mina [271]

Given:

v = 150d

v represents company's production for the coming year

d represents the number of days

150 is the daily production

The rate of change of the function representing the number of vehicles manufactured for the coming year is CONSTANT (150) , and its graph is a STRAIGHT LINE . So, the function is a LINEAR function.

I hope this helps!

4 0
3 years ago
Read 2 more answers
Convert 27day 8hour into second
Nataliya [291]
27 days and 8 hours = 656 hours
27 x 24 = 648
648 + 8 = 656
24 hours = 3,600 seconds
656 x 3,600 = 2,361,600 seconds

The answer is 2,361,600 seconds.
7 0
3 years ago
Solve by graphing: y=3(x-2)^2-3
forsale [732]

Answer:

thank you !!!!

Step-by-step explanation:

6 0
3 years ago
Having serious block because of the units The density of mercury is 13.6 g/cm3. What approximate mass of mercury is required to
mart [117]
I would approach the problem like this:

1 oz bottle.............................30cm^3
33 oz bottle.............................xcm^3

in a 33 oz bottle will be x=33*30=990cm^3
density=mm/v
13.6g/cm^3= m/ 990cm^3
m= 13.6 * 990=13464 g
or 13.464 kg in a 33 oz bottle
3 0
3 years ago
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