Answer:
9
Step-by-step explanation:
g(4)=4^2 =16, so we need to find f(16).
f(16)=16-7=<u>9</u>
Answer:
Total length of iron needed to make the square frame and two diagonals = 43.44 in (Approx)
Step-by-step explanation:
Given:
Length of diagonal = 9 in
Find:
Total length of iron needed to make the square frame and two diagonals.
Computation:
Area of square = 1/2(diagonal)²
Area of square = 1/2(9)²
Area of square = 40.5 in²
Area of square = Side × Side
40.5 in² = Side × Side
Side = 6.36 (approx)
Total length of iron needed to make the square frame and two diagonals = Permeter of square + (2 × diagonal)
⇒ (4 × 6.36) + (2 × 9)
⇒ (25.44) + (18)
⇒ 43.44 in
Total length of iron needed to make the square frame and two diagonals = 43.44 in (Approx)
Answer:
11 cm
Step-by-step explanation:
As Y is midpoint if XZ
XY=YZ=2a+1
WZ=WX+XY+YZ=28
a+1+2a+1+2a+1=28
5a+3= 28
5a=25
a=5
XY=2a+1
=2(5)+1
=10+1
=11 cm
Answer:
since we can't see the image, I'm just giving it a try
if it's wrong, it's fine for you to delete it
(see below)
Step-by-step explanation:
if one of the length is 5.6 units then the other will be 5 units
if one of the length is 4 units then the other will be 7 units
if one of the length is 2 units then the other will be 14 units
if one of the length is 1.86666666667 units then the other will be 15 units
if you're looking of an area, it might be 7 units
and I think that's all I've got
(hope it helps)
If p=4, plug in 4 to the equation.
1. q= 20 - 0.05 * 4^2
2. q= 20 - 0.05 * 16
3. q= 20 - 0.8
4. q= 19.2
