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3 years ago

Find the inverse of each function. h ( n ) = 4/n − 2

Mathematics

2 answers:

Darina [25.2K]3 years ago

7 0

$4(x + 2) = {h(n)}^{- 1}$

sladkih [1.3K]3 years ago

6 0

Answer: 4/(n+2)

h(n)=4/n-2

Let y=h(n),then,

→y=4/n-2

→4/n=y+2

→n=4/(y+2)

Interchanging the role of y and n here to find inverse,

y=4/(n+2) →inverse function

i.e. , inverse of h(n)=4/(n+2)

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3 years ago

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Mademuasel [1]

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======================================

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3 years ago

A line whose equation is 3/2y =3x-6 is parallel to a line with a general equation ax+by+c=0 passing through the points (3,2) . F

lana66690 [7]

Answer:

$\frac{1}{6} x+3y+\frac{13}{2}$ or x + 18y + 39

Step-by-step explanation:

$\frac{3}{2} y$ = $3x-6$

→ First multiply everything by 2 to get rid of the fraction

3y = 6x - 12

→ We want to find the equation that's parallel to this line and passes through (3 , 2). The first thing we know about parallel lines is that the gradient is the negative reciprocal so,

$3y = -\frac{1}{6} x+c$

→ Now we substitute in the values (3 , 2)

$6 =- \frac{1}{2}+c$

→ Add $\frac{1}{2}$ to both sides to isolate c

$\frac{13}{2} =c$

So the equation of the line that is parallel to $\frac{3}{2} y$ = $3x-6$ is $3y =- \frac{1}{6} x+\frac{13}{2}$ but we are not finished we are asked to but the equation in the format

ax + by + c = 0 so,

$3y =- \frac{1}{6} x+\frac{13}{2}$

Rearrange

$\frac{1}{6} x+3y+\frac{13}{2}$

If the question want's the answer in whole numbers then multiply everything by 6

x + 18y + 39

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