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Likurg_2 [28]
3 years ago
5

For some medical imaging, the scale of the image is 5 : 1. That means that if an image is 5 cm long, the corresponding length on

the person's body is 1 cm. Find the actual area of a lesion if its image has area 7.5 cm squared.
Mathematics
1 answer:
svlad2 [7]3 years ago
4 0
I believe it would be 1.5 cm squared because 7.5/5 = 5
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Graph a line with slope 3 passing through (-3, 2)
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(2,3)

Step-by-step explanation:

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<h2>Answer:</h2><h2>The probability of selecting a defective roll followed by another defective roll = \frac{1}{35}</h2>

Step-by-step explanation:

The total number of rolls in a box = 15

The number of defective items = 3

Two rolls are to be selected, one after the other. The probability of selecting a defective roll followed by another defective roll = ?

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In the healthy handwashing survey conducted by Bradley Corporation, a study was found that 64% of adult Americans operate the fl
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Answer:

<em>A) It fulfills the condition of binomial experiment</em>

<em>B) P (x=12) =0.1678</em>

<em>C)P ( x ≥16)= 0.1011</em>

<em>d) P (x>17) =0.0096 < 0.5</em>

Step-by-step explanation:

A. The binomial probability distribution has the following four properties

1. the outcomes of each trial maybe classified into success and failure.

2) the probability of success p remains constant for all trials.

3) the successive trials are all independent.

4) the experiment is repeated a fixed number of times ,n.

<em>These all conditions are fulfilled by the given question so it is a  binomial experiment. </em>

<em></em>

B) P (x=12) = 20C12 (0.64)^12 * (1-0.64)^8= 0.1678

C) P ( x ≥16) = P (x=16) + P (x=17) + P (x=18) + P (x=19)+ P (x=20)

where

P (x=16)= 20C16 (0.64)^16 * (1-0.64)^4= 0.0645

P (x=17)= 20C17 (0.64)^17 * (1-0.64)^3= 0.0270

P (x=18)= 20C18 (0.64)^18 * (1-0.64)^2= 0.0080

P (x=19)=20C19 (0.64)^10 * (1-0.64)^1= 0.0015

P (x=20)= 20C20 (0.64)^20 * (1-0.64)^0= 0.0001

so

P ( x ≥16)= 0.0645+ 0.0270 +0.0080+ 0.0015+0.0001= 0.1011

d) P (x>17)= P (x=17) + P (x=18) + P (x=19)+ P (x=20)

                    =0.0270 +0.0080+ 0.0015+0.0001

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From this we see that the probability of  more than 17  people who flush public toilets with their foot is unusual because it is far away from the mean which is supposed to be somewhere 0.5 in a given distribution.

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