The right answer should be “gravity acts to pull the object down.”
Hope this helps :)) and please correct me if I’m wrong :|
There’s nothing to see so there for I can’t help you
then the current will decrease.
hope this helps :)
Qs 1: Yes, there is a force, and distance, and they point in the same direction.
Qs 2: 420,000 J
Answer:
The value is
Explanation:
From the question we are told that
The magnitude of the first charge is ![q_1 = 31 \mu C = 31 *10^{-6} \ C](https://tex.z-dn.net/?f=q_1%20%3D%20%2031%20%5Cmu%20C%20%20%3D%20%2031%20%2A10%5E%7B-6%7D%20%5C%20%20C)
The position is y = 8 cm = 0.08 m
The magnitude of the second charge is ![q_1 = 55 \mu C = 55 *10^{-6} \ C](https://tex.z-dn.net/?f=q_1%20%3D%20%2055%20%5Cmu%20C%20%20%3D%20%2055%20%2A10%5E%7B-6%7D%20%5C%20%20C)
The position is x = 3 cm = 0.03 m
Generally the force exerted on the electron by the first charge is mathematically represented as
![F_1 = \frac{k * q_1 * e }{y^2}](https://tex.z-dn.net/?f=F_1%20%3D%20%20%5Cfrac%7Bk%20%2A%20%20q_1%20%2A%20e%20%7D%7By%5E2%7D)
Here k is the coulombs constants with value
=> ![k =9*10^{9}\ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}.](https://tex.z-dn.net/?f=%20k%20%3D9%2A10%5E%7B9%7D%5C%20kg%5Ccdot%20m%5E3%5Ccdot%20s%5E%7B-4%7D%20%5Ccdot%20A%5E%7B-2%7D.)
and e is the charge on a electron with value ![e = 1.60 *10^{-19} \ C](https://tex.z-dn.net/?f=e%20%3D%20%201.60%20%2A10%5E%7B-19%7D%20%5C%20C)
So
![F_1 = \frac{9*10^{9} * 31 *10^{-6} * 1.60 *10^{-19} }{0.08^2}](https://tex.z-dn.net/?f=F_1%20%3D%20%20%5Cfrac%7B9%2A10%5E%7B9%7D%20%2A%2031%20%2A10%5E%7B-6%7D%20%2A%201.60%20%2A10%5E%7B-19%7D%20%7D%7B0.08%5E2%7D)
![F_1 = 6.975 *10^{-11} j \ N](https://tex.z-dn.net/?f=F_1%20%3D%20%206.975%20%2A10%5E%7B-11%7D%20j%20%5C%20%20N)
Generally the force exerted on the electron by the first charge is mathematically represented as
![F_2 = \frac{k * q_2 * e }{x^2}](https://tex.z-dn.net/?f=F_2%20%3D%20%20%5Cfrac%7Bk%20%2A%20%20q_2%20%2A%20e%20%7D%7Bx%5E2%7D)
=>
=> ![F_2 = 8.8*10^{-11} i \ N](https://tex.z-dn.net/?f=F_2%20%3D%20%208.8%2A10%5E%7B-11%7D%20i%20%5C%20%20N)
Generally the net force exerted is mathematically represented as
![F_n = F_1 + F_2](https://tex.z-dn.net/?f=F_n%20%20%3D%20%20F_1%20%20%2B%20F_2)
So
![F_n = 6.975 *10^{-11} j + 8.8*10^{-11} i](https://tex.z-dn.net/?f=F_n%20%20%3D%20%206.975%20%2A10%5E%7B-11%7D%20j%20%20%2B%208.8%2A10%5E%7B-11%7D%20i%20)
The resultant of this net force is mathematically represented as
![F_nr = \sqrt{ (6.975 *10^{-11})^2 + (8.8*10^{-11})^2}](https://tex.z-dn.net/?f=F_nr%20%3D%20%20%5Csqrt%7B%20%286.975%20%2A10%5E%7B-11%7D%29%5E2%20%2B%20%288.8%2A10%5E%7B-11%7D%29%5E2%7D)
![F_nr = \sqrt{4.865*10^{-21} + 7.74*10^{-21}}](https://tex.z-dn.net/?f=F_nr%20%3D%20%20%5Csqrt%7B4.865%2A10%5E%7B-21%7D%20%2B%207.74%2A10%5E%7B-21%7D%7D)
![F_nr = 1.123 *10^{-10}\ N](https://tex.z-dn.net/?f=F_nr%20%3D%20%201.123%20%2A10%5E%7B-10%7D%5C%20N%20)
Generally this force can be represented as
![F_nr = ma](https://tex.z-dn.net/?f=F_nr%20%3D%20%20ma)
Here m is the mass of the electron with value
![m = 9.11 *10^{-31} \ kg](https://tex.z-dn.net/?f=m%20%3D%20%209.11%20%2A10%5E%7B-31%7D%20%5C%20%20kg)
=>
=>