Please visit out website at the URL below and you can click the "View Application" button under each listed Industry segment to view case studies of commonly EB welded applications.

https://www.ptreb.com/electron-beam-welding-applications

And for more general information on our welding process, we have an informational section you can peruse as well:

https://www.ptreb.com/electron-beam-welding-information

Good luck with your assignment- we are glad to hear they are teaching about EBW in high school!!!

8 0

3 years ago

Find the period of a wave with a frequency 40 kHz

Burka [1]

We know that frequency is an inverse value of time $f=\dfrac{1}{t}$ this implies that time is the inverse value of frequency $t=\dfrac{1}{f}$ .

Now since f is 40kHz, we can calculate period or duration for that matter time.

$t=\dfrac{1}{40\mathbf{kHz}}=0.000025\mathbf{s}=25\mathbf{\mu s}$

Hope this helps.

r3t40

4 0

3 years ago

Left arm has area 10.0 cm2, right has area 5.00 cm2. 100 g of water isadded to right side. a) Determine the length of the water

Masja [62]

Answer:

0.49 cm

Explanation:

We are given that

$A_1=10 cm^2$

$A_2=5 cm^2$

Mass of water,m=100 g

a. $\rho_w=1 g/cm^3$

Volume, $V=\frac{mass}{density}=\frac{100}{1}=100 cm^3$

Length of water column in the right arm= $L=\frac{V}{A_2}=\frac{100}{5}=20 cm$

b. $\rho_m=13.6 g/cm^3$

In equilibrium condition

Pressure at point A=Pressure at point B

$P+\rho_mg(h+h_2)=P+\rho_wgL$

$hA_1=h_2A_2$

$h_2=\frac{hA_1}{A_2}$

$13.6\times 9.8(h+h(\frac{A_1}{A_2}))=1\times 9.8\times 20$

$13.6\times h(\frac{A_2+A_1}{A_2})=20$

$h=\frac{20A_2}{13.6(A_2+A_1)}$

$h=\frac{20\times 5}{13.6\times (10+5)}=0.49 cm$

4 0

4 years ago

An astronaut is on the moon. He drops a hammer from a height of 3.2metres and it takes 2.0 seconds to reach the lunar landscape.

Anvisha [2.4K]

Answer:

1/6 m/s^2 ( about 1/6th gravity of Earth ( 9.81 m/s^2)

Explanation:

Displacement = yo + vo t - 1/2 a t^2

- 3.2 = 0 + 0 - 1/2 a(2.0)^2

- 3.2 = -2a

a = 3.2 / 2 = 1.6 m/s^2

6 0

3 years ago