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GarryVolchara [31]
3 years ago
10

How is acceleration calculated?

Physics
2 answers:
likoan [24]3 years ago
5 0

Acceleration equals the change in velocity divided by time.

That's the "time rate of change" of velocity.

steposvetlana [31]3 years ago
4 0

Answer:

Acceleration is the change in velocity divided by time

Explanation:

This is the correct answer because distance divided by time is the position. Speed multiplied by time is the distance. And acceleration is not just velocity, but the change in velocity over time.

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Which of the following can provide direct current?
Akimi4 [234]
The answer is d) batteries

mark as brainliest if it’s helpful
7 0
3 years ago
How facts differ from theroies?
frez [133]

Answer:

Facts and theories are two different things. In the scientific method, there is a clear distinction between facts, which can be observed and/or measured, and theories, which are scientists' explanations and interpretations of the facts.

Explanation:

3 0
4 years ago
Read 2 more answers
Practice
stiv31 [10]

Answer:

The answer is Letter B The car travel at a constant veloc

5 0
3 years ago
(a) You short-circuit a 20 volt battery by connecting a short wire from one end of the battery to the other end. If the current
erica [24]

(a) 1.11 \Omega

When the battery is short-cut, the only resistance in the circuit is the internal resistance of the battery. Therefore, we can apply Ohm's law:

r=\frac{V}{I}

where

V = 20 V is the voltage across the internal resistance of the battery

I = 18 A is the current flowing through it

Solving the equation,

r=\frac{20 V}{18 A}=1.11\Omega

(b) 360 W

The power generated by the battery is given by the equation

P=VI

where

V = 20 V is the voltage of the battery

I = 18 A is the current

Substituting into the formula,

P=(20 V)(18 A)=360 W

(c) 360 J

The energy dissipated by the internal resistance is given by

E=Pt

where

P = 360 W is the power generated

t = 1 s is the time

Solving the equation, we find

E=(360 W)(1 s)=360 J

(d) 1.65 A

The battery is now connected to a R=11 \Omega resistor. This means that the internal resistance of the battery is now connected in series with the other resistor R: so, the total resistance of the circuit is

R_T = r+R=1.11 \Omega +11 \Omega = 12.11 \Omega

And so, the current flowing through the circuit is

I=\frac{V}{R_T}=\frac{20 V}{12.11\Omega}=1.65 A

(e) 29.9 W

The power dissipated in the external resistor is given by

P=I^2 R

where

I = 1.65 A is the current

R=11 \Omega is the resistance

Solving the equation, we find

P=(1.65 A)^2(11 \Omega)=29.9 W

(f) 18.17 V

The terminals of the voltmeter are placed at the two end of the battery. The battery provides an emf of 20 V, however due to the internal resistance, some of this voltage is dropped across the internal resistance. Therefore, the actual potential difference that will be read by the voltmeter will be:

V=\epsilon - Ir =20 V -(1.65 A)(1.11 \Omega)=18.17 V

4 0
3 years ago
A.) If its booster rockets accelerate the space shuttle at 15m/s2, how high will it be one minute after launch?
poizon [28]

Answer:

27,000 m

450 m/s

Explanation:

Assuming the initial velocity is 0 m/s:

v₀ = 0 m/s

a = 15 m/s²

t = 60 s

A) Find: Δy

Δy = v₀ t + ½ at²

Δy = (0 m/s) (60 s) + ½ (15 m/s²) (60 s)²

Δy = 27,000 m

B) Find: v_avg

v_avg = Δy / t

v_avg = 27,000 m / 60 s

v_avg = 450 m/s

5 0
3 years ago
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