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USPshnik [31]
3 years ago
9

Two loudspeakers emit sound waves along the x-axis. The sound has maximum intensity when the speakers are 25 cm apart. The sound

intensity decreases as the distance between the speakers is increased, reaching zero at a separation of 62 cm .
What is the wavelength of the sound?
Physics
2 answers:
Elena-2011 [213]3 years ago
7 0

Answer:

74 cm

Explanation:

We are given that

The sound has maximum intensity when the separation between speaker=\Delta x_1=25 cm

The sound  intensity reaching zero when the separation between speakers=\Delta x_2=62 cm

We have to find the wavelength of the sound.

We know that

\Delta x_2-\Delta x_1=\frac{\lambda}{2}

Using the formula

62-25=\frac{\lambda}{2}

37=\frac{\lambda}{2}

\lambda=37\times 2=74 cm

Hence,the wavelength=74 cm

lubasha [3.4K]3 years ago
4 0

Answer:

λ = 74 cm

Explanation:

given,

Distance at which sound intensity is Maximum = 25 cm

Distance at which sound intensity is zero = 62 cm

When the sound intensity is maximum the condition is constructive interference.

When distance increases the path difference increases.

When means destructive interference the path difference must be increase from nλ to nλ + λ/2

now,

( nλ + λ/2 ) -  n λ = 62 - 25

λ/2 = 37

λ = 37 x 2

λ = 74 cm

Hence, the wavelength of the sound is equal to 74 cm.

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It is determined that a certain light wave has a wavelength of 3.012 ×10−12 m. The light travels at 2.99 ×108 m/s. What is the f
horsena [70]

Answer:

Explanation:

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velocity = 2.99*10^8 m/s

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2.99*10^8m/s = (f)(3.012*10^-12)

f=9.58*10^19 Hertz    

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Match the property of a sound wave to the correct definition. A. amplitude . B. frequency  . C. period . D. pitch  E. loudness 
Maru [420]

Amplitude: How dense the medium is in the compression part of the wave, and how empty the rarefied area is.

Frequency: The number of wavelengths that pass a position in 1 second.

loudness: The quality of the sound that is most closely linked to the amplitude of the sound wave.

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5 0
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A cyclist travels 1850 m north and then 1200 m south. Find both the distance it has traveled and the magnitude of its displaceme
finlep [7]

Answer:

The distance it has traveled is 3,050 m and the magnitude of its displacement is 650 m north.

Explanation:

Distance refers to the length between any two points in space, while displacement refers to the distance from a start position to an end position regardless of the path.

In other words, distance refers to how much space an object travels during its movement; is the quantity moved. It is also said to be the sum of the distances traveled. The distance traveled by a mobile is the length of its trajectory and it is a scalar quantity. In this case, the distance is calculated as:

1850 m + 1200 m= 3,050 m

Displacement refers to the distance and direction of the final position from the initial position of an object. The displacement effected is a vector quantity. The vector representing the displacement has its origin in the initial position, its end in the final position, and its module is the distance in a straight line between the initial and final positions. That is, when expressing the displacement it is done in terms of the magnitude with its respective unit of measurement and the direction because the displacement is a vector type quantity. Mathematically, the displacement (Δd) is calculated as:

Δd= df - di

where df is the final position and di is the initial position of the object.

In this case, the displacement is calculated as:

1850 m - 1200 m= 650 m

Since the distance to the north is greater, the direction of travel will be to the north.

<u><em>The distance it has traveled is 3,050 m and the magnitude of its displacement is 650 m north.</em></u>

6 0
2 years ago
1)
Ket [755]

Answer:

1) D

2) A

Explanation:

1) Each group has the same number of valence electrons, which are the outer electrons.

2) Ionic bonds are between a metal and non - metal, the metal being sodium and the non - metal being chlorine.

3 0
3 years ago
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