A cylinder with a mass M and radius r is floating in a pool of liquid. The cylinder is weighted on one end so that the axis of t
1 answer:
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Answer:
The flux will be nine times as great.
Explanation:
The electric flux due to a charge Q located in the center of a sphere can be obtained using Gauss's law. Considering a Gaussian surface in the form of a sphere of radius r:
The electric field (E) is parallel to the surface vector (dS), so
Since the electric flux is proportional to the square of the sphere's radius, if radius of sphere were tripled, the flux will be nine times as great.
Answer:
Electric flux in a) , b) and c) is same which is 0.373 × 10 ⁶ N m²/C
Explanation:
given,
surface charge (q) = 3.3 × 10⁻⁶ C
to calculate electric flux = ?
a) radius = 0.76 m
area of sphere = 4 π r²
electric flux =
electric flux =
flux = 0.373 × 10 ⁶ N m²/C
electric flux in the other two cases will also be same as electric flux is independent of area
so, Electric flux in a) , b) and c) is same which is 0.373 × 10 ⁶ N m²/C