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Sedaia [141]
3 years ago
15

A cylinder with a mass M and radius r is floating in a pool of liquid. The cylinder is weighted on one end so that the axis of t

he cylinder stands vertically. The total length of the cylinder is L. The density of the fluid is rho.
a. When the cylinder is in equilibrium, a portion of it is submerged in the liquid. What is the vertical length h of this submerged portion? Your answer should use only the given symbols M, r, L, and rho as necessary, as well as the constant g.
b. The cylinder is now displaced a distance y from the equilibrium position, such that |y| < h, and released from rest. Let the +y-axis be upward, so that if the cylinder is pulled up, y is positive, but if it is pushed down, y is negative. Immediately after it is released, what is the y-component of the acceleration ay of the cylinder? Your answer should use only the given symbols M, r, L, y, and rho as necessary, as well as the constant g.
c. The result of part (b) implies the cylinder is now in simple harmonic motion. What is the period T of the cylinder's oscillations
Physics
1 answer:
Blizzard [7]3 years ago
8 0

Answer:

acylinder whit is yoiyes

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A heat engine extracts 42. 53 kj from the hot reservior and exhausts 17. 69 kj into the cold reservior. what is the work done?
ludmilkaskok [199]

The answer is  24.84kJ.

We apply the expression for the work done by the heat engine is,

W=E_{i n}-E_{o u t}. Putting all given values in the equation we get the final answer.

What is heat engine?

  • A heat engine is a machine that uses heat to generate power. It draws heat from a reservoir, uses that heat to produce work, such as move a piston or lift weights, and then releases that heat energy into the sink.
  • We are given:The heat input is $E_{i n}=42.53 \mathrm{~kJ}$. The heat output is $E_{o u t}=17.69 \mathrm{~kJ}$.
  • The expression for the work done by the heat engine is,W=E_{i n}-E_{o u t}
  • Substituting the given values in the above expression, we will getW =42.53 \mathrm{~kJ}-17.69 \mathrm{~kJ}=24.84kJ.
  • Thus, the work done by the heat engine is 24.84kJ.

To learn more about heat engine visit: brainly.com/question/15735984

#SPJ4

6 0
2 years ago
The voltage across the secondary winding is 10,000 V, and the voltage across the primary winding is 25,000 V. If the primary win
Allisa [31]

<u>Answer</u>

80 coils


<u>Explanation</u>

The turn rule of a transformer says that, the amount of voltage induced in the secondary coil is proportional to the number of coil. It is simplified by the ratio:

N<em>p/</em><em>N</em><em>s  =  </em><em>V</em><em>p/</em><em>V</em><em>s</em>

200/Ns  = 25,000/10,000

200 × 10,000  = 25,000Ns

2,000,000 = 25000Ns

Dividing both sides by 25,000,

Ns = 2,000,000/25,000

       = 80 coils




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