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2 years ago

How are the concentrations of hydrogen ions and hydroxide ions related in an aqueous solution?

Chemistry

2 answers:

12345 [234]2 years ago

7 0

Answer:

An Arrhenius acid increases the concentration of hydrogen (H+) ions in an aqueous solution, and

Arrhenius base increases the concentration of hydroxide (OH–) ions in an aqueous solution.

Jlenok [28]2 years ago

5 0

Answer:

An Arrhenius acid increases the concentration of hydrogen (H+) ions in an aqueous solution, while an Arrhenius base increases the concentration of hydroxide (OH–) ions in an aqueous solution.

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Explanation:

No because the person on the bike is going faster then the person on foot.

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2 years ago

The zinc within a copper-plated penny will dissolve in hydrochloric acid if the copper coating is filed down in several spots (s

Mrac [35]

Answer:

Mass of hydrogen gas evolved is 0.0749 grams.

Explanation:

Total pressure of the gases = p = 758 mmHg

Vapor pressure of water = 23.78 mmHg

Pressure of hydrogen gas ,P = p - 23.78 mmHg = 758 mmHg - 23.78 mmHg

P = 734.22 mmHg = $\frac{734.22}{760} atm=0.966 atm$

Temperature of of hydrogen gas ,T= 25°C =298.15 K

Volume of hydrogen gas = V = 0.949 L

Moles of hydrogen gas =n

PV = nRT (Ideal gas equation )

$n=\frac{PV}{RT}=\frac{0.966 atm\times 0.949 L}{0.0821 atm L/mol K\times 298.15 K}$

n = 0.03745 mol

Moles of hydrogen gas = 0.03745 mol

Mass of 0.03745 moles of hydrogen gas = 0.03745 mol × 2 g/mol = 0.0749 g

Mass of hydrogen gas evolved is 0.0749 grams.

3 0

3 years ago

What is the mass of solute dissolved in 50,0 g of 12.5% saline solution? A) 7.148 B) 6.258 C) 43.88 D) 4.00 g

Marizza181 [45]

Answer:

6.25 grams is the mass of solute dissolved.

Explanation:

w/w % : The percentage mass or fraction of mass of the of solute present in total mass of the solution.

$w/w\%=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100$

Mass of the solution = 50.0 g

Mass of the solvent = x

w/w % = 12.5%

$12.5\%=\frac{x}{50.0 g}\times 100$

x = 6.25 g

6.25 grams is the mass of solute dissolved.

6 0

2 years ago

Scoring Scheme: 3-3-2-1 Part I. How many mL of 6 M NaOH stock solution should be used to prepare the 500 mL of 0.2 M NaOH? Pleas

Orlov [11]

Answer : The volume of 6M NaOH stock solution is, 16.7 mL

Explanation :

To calculate the volume of NaOH stock solution, we use the equation given by neutralization reaction:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of NaOH stock solution.

$M_2\text{ and }V_2$ are the molarity and volume of NaOH.

We are given:

$M_1=6M\\V_1=?\\M_2=0.2M\\V_2=500mL$

Putting values in above equation, we get:

$6M\times V_1=0.2M\times 500mL\\\\V_1=16.7mL$

Thus, the volume of 6M NaOH stock solution is, 16.7 mL

4 0

3 years ago

I need help with electron affinity chemistry problem. I’m having a tough time.

ExtremeBDS [4]

Answer:

Br Be Ge

Explanation:

Increases in electron affinity

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3 years ago