How many moles of oxygen are needed to completely react with 9.5 g of sodium
1 answer:
<span>4 Na + O</span>₂<span> = 2 Na</span>₂<span>O
</span>
4* 23 g Na --------> 16 g O₂
9.5 g Na ------------> ?
Mass of O₂ = 9.5 * 16 / 4 * 23
Mass = 152 / 92
Mass = 1.6521 g of O₂
Molar mass O₂ = 16.0 g/mol
1 mole O₂ ------------ 16.0 g
? mole O₂ ------------ 1.6521 g
mole O₂ = 1.6521 * 1 / 16.0
≈ 0.10325 moles of O₂
hope this helps!
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