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Airida [17]
2 years ago
6

The formula v equals the square root of the quantity 64 multiplied by h end of quantity gives the velocity v in feet per second

of an object that has fallen h feet. Find the velocity of an object that has fallen 84 feet. Round to the nearest hundredth.
A. 51.85 ft/sec

B. 5376 ft/sec

C. 12.96 ft/sec

D. 73.32 ft/sec
Mathematics
2 answers:
NemiM [27]2 years ago
5 0
The equation is derived from the conservation of energy, specifically from potential energy stored at a given height in a gravitational field.

When potential energy is completely converted to kinetic energy you have:

(mv^2)/2=mgh  divide both sides by the mass m

v^2/2=gh  multiply both sides by 2

v^2=2gh take the square root of both sides

v=√(2gh)  and working with imperial units for acceleration due to gravity, g=-32ft/s^2

v=√(-64h)  but the change of h as it falls is negative h so

v=-√(64h) so if an object falls from a height of 88ft we have:

v=-√(64*84)

v=-√5376

v≈-73.32 ft/sec (to the nearest hundredth of a foot per second)

Note that this is the velocity, it is negative 73.32 ft/sec.

The question inadvertently asked for velocity and provided answers for SPEED.  Velocity is a vector and has both magnitude and direction, whereas speed just has magnitude.

So its final speed is 73.32 ft/sec

So if they actually wanted velocity none of their answers is correct :P
KATRIN_1 [288]2 years ago
4 0

Answer:

d 73.32

Step-by-step explanation:

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Step-by-step explanation:

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Determine the coordinates of the intersection of the diagonals of square ABCD with verticals A(-4,6), B(5,6) C(4,-2), and D(-5,-
timama [110]

Given:

Vertices of a square are A(-4,6), B(5,6) C(4,-2), and D(-5,-2).

To find:

The intersection of the diagonals of square ABCD.

Solution:

We know that diagonals of a square always bisect each other. It means intersection of the diagonals of square is the midpoint of diagonals.

In the square ABCD, AC and BD are two diagonals. So, intersection of the diagonals is the midpoint of both AC and BD.

We can find midpoint of either AC or BD because both will result the same.

Midpoint of A(-4,6) and C(4,-2) is

Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

Midpoint=\left(\dfrac{-4+4}{2},\dfrac{6+(-2)}{2}\right)

Midpoint=\left(\dfrac{0}{2},\dfrac{6-2}{2}\right)

Midpoint=\left(\dfrac{0}{2},\dfrac{4}{2}\right)

Midpoint=\left(0,2\right)

Therefore, the intersection of the diagonals of square ABCD is (0,2).

4 0
3 years ago
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