Question

What is the chemical formula for the compound formed between vanadium(iii) and the bromate ion?

Answer 1

Vanadium (III) Bromate is V(BrO3)3.

Answer 2

Answer:

$V(BrO_3)_3$

Explanation:

Hello,

In this case, vanadium is specified with +3 as its oxidation state, however it is stated that vanadium is combined with the bromate ion, which according to the IUPAC rules, accounts for bromine's last oxidation state, that is +5, in such a way, we build up the bromate ion forming the bromic acid shown below:

$Br^{+5}+O^{-2}-->Br_2O_5\\Br_2O_5+H_2O-->HBrO_3$

Such bromate comes from the bromic acid's anion, this is $(BrO_3)^-$, thus, the required formula of the vanadium (III) bromate turns out into:

$V^{+3}(BrO_3)^-_3\\V(BrO_3)_3$

Best regards.