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rusak2 [61]
3 years ago
13

Please help with an easy percentage yield question ASAP!!! Would really appreciate!

Chemistry
1 answer:
Brut [27]3 years ago
7 0

Answer:

The mass percentage yield is 85%

Explanation:

<u>Step 1: </u>The balanced equation

2 C7H6O3 +  (CH3CO)2CO → 2 C9H8O4 + H20

<u>Step 2</u>: Given data

mass of salicylic acid = 1.03 grams

Volume of acetic anhydride = 2.00 mL = 2*10^-3 L

The product is 1.16 g aspirin synthesized

Molar mass of salicylic acid = 138.12 g/mole

Molar mass of aspirin = 180.16 g/mole

Density of acetic anhydride = 1.0820 g/mL

<u>Step 3</u>: Calculated moles of salicylic acid

Number of moles of salicylic acid = mass of salicylic acid / Molar mass of salicylic acid

Number of moles of salicylic acid = 1.03 grams / 138.12 g/mole

Number of moles of salicylic acid =0.0075 moles

Step 4: Calculated mass acetic anhydride

mass of acetic anhydride = 1.0820 g/mL * 2 mL = 2.164 grams

Step 5: Calculate number of moles of acetic anhydride

Number of moles = 2.164 grams / 102.09 g/moles

Number of moles = 0.0212 moles

<u>Step 6</u>: Find amount of reacting moles

C7H6O3 is the limiting reactant, there will react 0.0075 moles

Since for 2 moles C7H6O3 consumed, we need 1 mole of (CH3CO)2CO to produce 2 moles of C9H804

So for 0.0075 moles C7H6O3 consumed, we produce 0.0075 moles of C9H8O4

<u>Step 7</u>: Calculate mass of aspirin

mass of aspirin = 0.0075 moles * 180 g/mole = 1.35 grams

<u>Step 8:</u> Calculate the mass percentage yield

(1.16 grams / 1.35 grams) * 100% = 85 %

The mass percentage yield is 85%

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<u>Answer:</u> The standard free energy change of formation of S^{2-}(aq.) is 92.094 kJ/mol

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\Delta G^o_{rxn}=\sum [n\times \Delta G^o_f_{(product)}]-\sum [n\times \Delta G^o_f_{(reactant)}]

The equation for the Gibbs free energy change of the above reaction is:

\Delta G^o_{rxn}=[(2\times \Delta G^o_f_{(Ag^+(aq.))})+(1\times \Delta G^o_f_{(S^{2-}(aq.))})]-[(1\times \Delta G^o_f_{(Ag_2S(s))})]

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285.794=[(2\times 77.1)+(1\times \Delta G^o_f_{(S^{2-}(aq.))})]-[(1\times (-39.5))]\\\\\Delta G^o_f_{(S^{2-}(aq.))=92.094J/mol

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