Answer:
a common temperature is reached.
Explanation:
The principle of heat transfer is that heat flows from a substance of higher temperature to that of lower temperature until when a common temperature is reached.
For ice on getting in contact with a hot body; it changes to water at 0°c utilising the latent heat of fusion. After ice has been converted to water at 0°c, water starts increasing in temperature till a common temperature is reached.
We're given the velocity at two points, and the time between the mentioned two points.
What we'll be calculating is the average acceleration (not to be confused with instantaneous acceleration).
Given two points, lets call them initial and final, the average acceleration is calculated as:
![a= \frac{v_f-v_0}{t}](https://tex.z-dn.net/?f=a%3D%20%5Cfrac%7Bv_f-v_0%7D%7Bt%7D)
In which
![v_f](https://tex.z-dn.net/?f=v_f)
is the final velocity (in your problem equal to 1m/s),
![v_0](https://tex.z-dn.net/?f=v_0)
is the initial velocity (in your problem equal to 16 m/s), and
![t](https://tex.z-dn.net/?f=t)
the time between two points (in your problem equal to 2s).
So, we plug-in our known values:
The answer is -7.5m/s^2.
Answer:
Explanation:
Relation between Celsius and Kelvin is
K = C + 273
Relation between Kelvin and Fahrenheit is
![\frac{K-273}{100}=\frac{F -32}{180}](https://tex.z-dn.net/?f=%5Cfrac%7BK-273%7D%7B100%7D%3D%5Cfrac%7BF%20-32%7D%7B180%7D)
(a) 379 K
Relation between Celsius and Kelvin is
K = C + 273
So, C = K - 273 = 379 - 273 = 106
Thus, 379 K = 106°C.
(b) 379 K
Relation between Kelvin and Fahrenheit is
![\frac{K-273}{100}=\frac{F -32}{180}](https://tex.z-dn.net/?f=%5Cfrac%7BK-273%7D%7B100%7D%3D%5Cfrac%7BF%20-32%7D%7B180%7D)
![\frac{379-273}{100}=\frac{F -32}{180}](https://tex.z-dn.net/?f=%5Cfrac%7B379-273%7D%7B100%7D%3D%5Cfrac%7BF%20-32%7D%7B180%7D)
F = 222.8°F
Thus, 379 K = 222.8°F
(c) 1.04 x 10^2 K = 104 K
Relation between Celsius and Kelvin is
K = C + 273
So, C = K - 273 = 104 - 273 = -169
Thus, 104 K = - 169°C.
(d) 1.04 x 10^2 K = 104 K
Relation between Kelvin and Fahrenheit is
![\frac{K-273}{100}=\frac{F -32}{180}](https://tex.z-dn.net/?f=%5Cfrac%7BK-273%7D%7B100%7D%3D%5Cfrac%7BF%20-32%7D%7B180%7D)
![\frac{104-273}{100}=\frac{F -32}{180}](https://tex.z-dn.net/?f=%5Cfrac%7B104-273%7D%7B100%7D%3D%5Cfrac%7BF%20-32%7D%7B180%7D)
F =- 272.2°F
Thus, 104 K = - 272.2°F
Answer:
Explanation: divide 280 by 68 which would = 4 I think