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andriy [413]
3 years ago
12

When a substance cools down, is it releasing or absorbing energy?

Chemistry
1 answer:
Wewaii [24]3 years ago
4 0
<span>When something becomes cold or freezes such as water,it is releasing energy.The temperature continues to decrease more energy is given up and released.It stays a constant temperature as more energy is released to maintain the temperature needed to achieve the correct degree needed.</span>
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1.
Mazyrski [523]

1)   {ca}^{2 + }  = cation \\ {br}^{2 - }  = anion

7 0
3 years ago
Read 2 more answers
Acetylene gas (ethyne; HC = CH) burns in an oxyacetylene torch to produce carbon dioxide and water vapor. The heat of reaction f
Yanka [14]

The mass of CO2 produced by 26g of acetylene is 88g.

Given ,

In an oxyacetylene torch, acetylene gas (ethyne; HCCH) burns to produce carbon dioxide and water vapour.

The acetylene combustion reaction is given by,

H2O + HCCH + 5/2 O=O 2CO2

Heat of reaction for acetylene combustion = 1259kj/mol

CO2 has a molecular mass of 44g/mol.

2 moles of CO2 have a molecular mass of 88g.

On combustion, 1 mole of acetylene yields 2 moles of CO2.

Thus, 26g of acetylene produces 88g of CO2 when burned.

As a result, the mass of carbon dioxide produced by 26g of acetylene is 88g.

Learn more about acetylene here :

brainly.com/question/15346128

#SPJ4

6 0
1 year ago
__C2H4+__O2--&gt;__CO2+__H2O
mihalych1998 [28]

Answer:

Here is your answer mate :D

3 0
3 years ago
If you visited a savanna you most likely see what
Jobisdone [24]
You would most likely see rolling grasslands. There would be isolated trees and shrubs. Not enough rain falls in the savanna to support forests.
:) hope this helps
8 0
3 years ago
Read 2 more answers
What is the boiling point of a solution containing 203 g of ethylene glycol (C2H6O2) and 1035 g of water? (Kb for water is 0.52
Andru [333]

Answer:

101,37°C

Explanation:

Boiling point elevation is one of the colligative properties of matter. The formula is:

ΔT = kb×m <em>(1)</em>

Where:

ΔT is change in boiling point: (X-100°C) -X is the boiling point of the solution-

kb is ebulloscopic constant (0,52°C/m)

And m is molality of solution (mol of ethylene glycol / kg of solution). Moles of ethylene glycol (MW: 62,07g/mol):

203g × (1mol /62,07g) = <em>3,27moles of ethlyene glycol</em>

<em />

Molality is: 3,27moles of ethlyene glycol / (1,035kg + 0,203kg) = 2,64m

Replacing these values in (1):

X - 100°C = 0,52°C/m×2,64m

X - 100°C = 1,37°C

<em>X = 101,37°C</em>

<em></em>

I hope it helps!

7 0
3 years ago
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