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3 years ago

URGENT!!

Chemistry

1 answer:

tresset_1 [31]3 years ago

5 0

Answer:

False

Explanation:

Ocean waves are something you can physically see whereas Gamma Rays and Light Waves are something on the Electromagnetic Spectrum.

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Write the dissociation equation for, and give the proper concentrations for a 0.25M K2SO4 solution

weeeeeb [17]

Answer: $K_2SO_4\rightarrow 2K^++SO_4^{2-}$

concentration of $K^+$ = 0.50 M

concentration of $SO_4^{2-}$ = 0.25 M

Explanation:

The dissociation equation of $K_2SO_4$ is:

$K_2SO_4\rightarrow 2K^++SO_4^{2-}$

According to stoichiometry:

1 mole of $K_2SO_4$ gives 2 moles of $K^+$

Thus 0.25 moles of $K_2SO_4$ gives = $\frac{2}{1}\times 0.25=0.50$ moles of $K^+$

Similarly,

1 mole of $K_2SO_4$ gives = 1 mole of $SO_4^{2-}$

Thus 0.25 moles of $K_2SO_4$ gives = $\frac{1}{1}\times 0.25=0.25$ moles of $SO_4^{2-}$

Thus the concentration of $K^+$ and $SO_4^{2-}$ are 0.50 M and 0.25 M respectively.

8 0

4 years ago

When mixing eggs flour and sugar what type of change happens?

Jet001 [13]

Chemical change since when you mix eggs flour and sugar together, it isn't egg, sugar or flour anymore

3 0

3 years ago

The structure of an atom is defined by two numbers: the proton (atomic) number and the mass (nucleon) number. What is the electr

zzz [600]

Answer:

Explanation:

electronic configuration of an atom with proton number 5 is 2, 3

since no. of proton = no. of electron

3 0

3 years ago

How many electrons would be transferred in either a voltaic or electrolytic cell that uses the following half reactions

omeli [17]

Answer:

Numbers of electrons transferred in the electrolytic or voltaic cell is 6 electrons.

Explanation:

$Fe^{3+} (aq) + 3 e^-\rightarrow Fe (s) ,E^o = -0.036 V$

$Mg^{2+}(aq) + 2 e^- \rightarrow Mg (s),E^o = -2.37 V$

The substance having highest positive reduction $E^o$ potential will always get reduced and will undergo reduction reaction.

Reduction : cathode

$Fe^{3+} (aq) + 3 e^-\rightarrow Fe (s) ,E^o = -0.036 V$ ..[1]

Oxidation: anode

$Mg(s)\rightarrow Mg^{2+}(aq) + 2 e^-,E^o = 2.37 V$ ..[2]

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{red,cathode}-E^o_{red,anode}$

$E^o_{cell}=-0.036V-(-2.37 V)=2.334 V$

The overall reaction will be:

2 × [1] + 3 × [2] :

$2Fe^{3+} (aq) + 3Mg(s)+6e^-\rightarrow 2Fe (s)+3Mg^{2+}(aq)+6e^-$

Electrons on both sides will get cancelled :

$2Fe^{3+} (aq) + 3Mg(s)\rightarrow 2Fe (s)+3Mg^{2+}(aq)$

Numbers of electrons transferred in the electrolytic or voltaic cell is 6 electrons.

5 0

4 years ago

How many grams of solid potassium hypochlorite should be added to 2.00 L of a 0.244 M hypochlorous acid solution to prepare a bu

Olin [163]

Answer:

8.2763 g

Explanation:

Considering the Henderson- Hasselbalch equation for the calculation of the pH of the buffer solution as:

pH=pKa+log[base]/[acid]

Where Ka is the dissociation constant of the acid.

Given that the acid dissociation constant = 3.5×10⁻⁸

pKa = - log (Ka) = - log (3.5×10⁻⁸) = 7.46

Given concentration of acid = [acid] = 0.244 M

pH = 6.733

So,

6.733 = 7.46+log[base]/0.244

[Base] = 0.0457 M

Given that Volume = 2 L

So, Moles = Molarity × Volume

Moles = 0.0457 × 2 = 0.0914 moles

Molar mass of potassium hypochlorite = 90.55 g/mol

Mass = Moles × Molar mass = (0.0914 × 90.55) g = <u>8.2763 g</u>

7 0

4 years ago