Answer:
1.125m/s^2
Explanation:
Since acceleration is defined as the rate of change in velocity with respect to time. Mathematically
v^2= u^2+2as
Where a,v,u and s are the acceleration, final velocity, initial velocity and distance respectively.
a = ?
u = 0m/s
v = 15m/s
s = 100m
Substituting the values into the formula above
v^2= u^2+2as
15^2=0^2+2×a×100
225= 0+200a
225= 200a
Divide both sides by 200
225/200 = 200a/200
a= 1.125m/s^2
Hence the acceleration of the car is 1.125m/s^2.
Note that the car accelerated uniformly from rest, that was why the initial velocity was 0m/s
Answer:
The banking angle is 23.84 degrees.
Explanation:
Given that,
Radius of the curve, r = 194 m
Speed of the car, v = 29 m/s
On the banked curve, the centripetal force is balanced by the force of friction such that,
So, the banking angle is 23.84 degrees. Hence, this is the required solution.
