Answer:
R = 0.0015Ω
Explanation:
The formula for calculating the resistivity of a material is expressed as;
ρ = RA/l
R is the resistance
ρ is the resistivity
A is the area of the wire
l is the length of the wire
Given
l = 85cm = 0.85m
A = πr²
A = 3.14*0.0018²
A = 0.0000101736m²
ρ = 1.75 × 10-8Ωm.
Substitute into the formula
1.75 × 10-8 = 0.0000101736R/0.85
1.4875× 10-8 = 0.0000101736R
R = 1.4875× 10-8/0.0000101736
R = 0.0015Ω
Using F=Ma
where a= F/M = 12/3 = 4ms-²
Answer:
Original speed of the mess kit = 4.43 m/s at 50.67° north of east.
Explanation:
Let north represent positive y axis and east represent positive x axis.
Here momentum is conserved.
Let the initial velocity be v.
Initial momentum = 4.4 x v = 4.4v
Velocity of 2.2 kg moving at 2.9 m/s, due north = 2.9 j m/s
Velocity of 2.2 kg moving at 6.8 m/s, 35° north of east = 6.9 ( cos 35i + sin35 j ) = 5.62 i + 3.96 j m/s
Final momentum = 2.2 x 2.9 j + 2.2 x (5.62 i + 3.96 j) = 12.364 i + 15.092 j kgm/s
We have
Initial momentum = Final momentum
4.4v = 12.364 i + 15.092 j
v =2.81 i + 3.43 j
Magnitude
![v=\sqrt{2.81^2+3.43^2}=4.43m/s](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B2.81%5E2%2B3.43%5E2%7D%3D4.43m%2Fs)
Direction
![\theta =tan^{-1}\left ( \frac{3.43}{2.81}\right )=50.67^0](https://tex.z-dn.net/?f=%5Ctheta%20%3Dtan%5E%7B-1%7D%5Cleft%20%28%20%5Cfrac%7B3.43%7D%7B2.81%7D%5Cright%20%29%3D50.67%5E0)
50.67° north of east.
Original speed of the mess kit = 4.43 m/s at 50.67° north of east.
Answer:yes
Explanation:The constan acceleration means that it wont stop moving but if you kick it a different direction then it will change direction
Answer:
3.7 km/h
Explanation:
Let's call v the proper speed of the boat and v' the speed of the water in the river.
When the boat travels in the direction of the current, the speed of the boat is:
v + v'
And it covers 50 km in 3 h, so we can write
(1)
When the boat travels in the opposite direction, the speed of the boat is
v - v'
And it covers 50 km in 5.4 h, so
(2)
So we have a system of two equations: by solving them simultaneously, we find the value of v and v':
![v+v'=16.7 \\v-v'=9.3](https://tex.z-dn.net/?f=v%2Bv%27%3D16.7%20%5C%5Cv-v%27%3D9.3)
Subtracting the second equation from the first one we get:
![(v+v')-(v-v')=16.7-9.3\\2v'=7.4\\v'=3.7](https://tex.z-dn.net/?f=%28v%2Bv%27%29-%28v-v%27%29%3D16.7-9.3%5C%5C2v%27%3D7.4%5C%5Cv%27%3D3.7)
So, the speed of the water is 3.7 km/h.