Answer:
1362000 kgm/s
Explanation:
So the total mass combination of the plane and the people inside it is
M = 35000 + 160*65 = 45400 kg
After 15 seconds at an acceleration of 2 m/s2, the plane speed would be
V = 2*15 = 30 m/s
So the magnitude of the plane 15s after brakes are released is
MV = 45400 * 30 = 1362000 kgm/s
Answer:
The velocity of the student has after throwing the book is 0.0345 m/s.
Explanation:
Given that,
Mass of book =1.25 kg
Combined mass = 112 kg
Velocity of book = 3.61 m/s
Angle = 31°
We need to calculate the magnitude of the velocity of the student has after throwing the book
Using conservation of momentum along horizontal direction
![m_{b}v_{b}\cos\theta= m_{c}v_{c}](https://tex.z-dn.net/?f=m_%7Bb%7Dv_%7Bb%7D%5Ccos%5Ctheta%3D%20m_%7Bc%7Dv_%7Bc%7D)
![v_{s}=\dfrac{m_{b}v_{b}\cos\theta}{m_{c}}](https://tex.z-dn.net/?f=v_%7Bs%7D%3D%5Cdfrac%7Bm_%7Bb%7Dv_%7Bb%7D%5Ccos%5Ctheta%7D%7Bm_%7Bc%7D%7D)
Put the value into the formula
![v_{c}=\dfrac{1.25\times3.61\times\cos31}{112}](https://tex.z-dn.net/?f=v_%7Bc%7D%3D%5Cdfrac%7B1.25%5Ctimes3.61%5Ctimes%5Ccos31%7D%7B112%7D)
![v_{c}=0.0345\ m/s](https://tex.z-dn.net/?f=v_%7Bc%7D%3D0.0345%5C%20m%2Fs)
Hence, The velocity of the student has after throwing the book is 0.0345 m/s.
Answer: rotational force
Explanation:
Torque is the twisting force which cause rotation and the axis of rotation is the point at which the object rotates.
Torque is a rotational force as it leads to the rotation of an object about an axis. Force simply means a pull or push. When an unbalanced ball acts on a force, the ball, the ball will be moved towards the linear motion.
Then, the unbalanced force that is acting in the ball produces torque which causes the ball's rotational motion.
Answer: 3 m.
Explanation:
Neglecting the mass of the seesaw, in order the seesaw to be balanced, the sum of the torques created by gravity acting on both children must be 0.
As we are asked to locate Jack at some distance from the fulcrum, we can take torques regarding the fulcrum, which is located at just in the middle of the length of the seesaw.
If we choose the counterclockwise direction as positive, we can write the torque equation as follows (assuming that Jill sits at the left end of the seesaw):
mJill* 5m -mJack* d = 0
60 kg*5 m -100 kg* d =0
Solving for d:
d = 3 m.