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3 years ago

Why does a buoyant force act on every object in a fluid?

Physics

1 answer:

Georgia [21]3 years ago

8 0

Answer:

The buoyant force comes from the pressure exerted on the object by the fluid. Because the pressure increases as the depth increases, the pressure on the bottom of an object is always larger than the force on the top - hence the net upward force.

Explanation:

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The length of a rectangle is increasing at a rate of 4 cm/s and its width is increasing at a rate of 6 cm/s. When the length is

Fudgin [204]

Answer:

24cm/s

Explanation:

A=L*w

A'=L'*w'

L=13

w=5

L'=4

w'=6

A=?

A'=?

A=L*w

A=13*5

A=65

A'=L'*w'

A'=4*6

A'=24

*the given lengths are just to throw you off*

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3 years ago

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Yuki888 [10]

Answer:

i tried :( sorry

Explanation:

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3 years ago

A car starts from rest. 900 s later it is traveling at a velocity of 30 m/s north. Which of the following equations should you u

gogolik [260]

(vx)f=(vx)i + a(t)
since it starts from rest the initial velocity is zero so you can do some algebra and get your (a).

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3 years ago

A golf ball with m = 46 g is struck a blow which makes an angle of 45o with the horizontal. The drive lands 200 m away on a flat

AfilCa [17]

Answer:

Average force will be equal to 2908.57 N

Explanation:

We have given mass of the ball m = 46 gram = 0.046 kg

Let velocity at which ball is projected is u m/sec

Angle at which ball is projected $\Theta =45^{\circ}$

Range of the ball is given R = 200 m

Range is equal to $R=\frac{u^2sin2\Theta }{g}$

$200=\frac{u^2sin(90^{\circ})}{9.8}$

$u^2=1960$

u = 44.27 m/sec

Change in momentum of the ball is equal to $P=mu=0.46\times 44.27=20.36kgm/sec$

Time of impact is given $dt=7ms=0.007sec$

Force is equal to rate of change of momentum

So force $F=\frac{dP}{dt}=\frac{20.36}{0.007}=2908.57N$

Force will be equal to 2908.57 N

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3 years ago

How long will be required for an object to go from a speed of 22m/s to a speed of 27m/s if the acceleration is 5.93m/s^2 ?

mario62 [17]

Answer:

Required time, t = 0.84 seconds

Explanation:

It is given that,

Initial speed of an object, u = 22 m/s

Final velocity of an object, v = 27 m/s

Acceleration, a = 5.93 m/s²

We have to find the time required for an object to go a speed of 22 m/s to a speed of 27 m/s. It can be solved by using first equation of motion as:

$v=u+at$

Where

t = time

$t=\dfrac{v-u}{a}$

$t=\dfrac{27\ m/s-22\ m/s}{5.93\ m/s^2}$

t = 0.84 seconds

Hence, the time required for an object is 0.84 seconds.

4 0

3 years ago