The frequency, the speed and the wavelength of a wave are related by the following equation:

(1)
where
f is the frequency

is the wavelength
v is the wave speed
The speed of the wave does depend only on the properties of the medium, so since the wave is still traveling in air, the medium has not changed and therefore the speed remains the same. We see instead from eq.(1) that the frequency is inversely proportional to the wavelength, so if the wavelength is decreased by half, we see that the frequency will double.
Answer:
The angular velocity I would have to rotate it in order to generate an emf of amplitude 1.0 V is 254.65 rad/s
Explanation:
given information:
B = 0.5 mT = 0.0005 T
N = 1000
r = 5 cm = 0.05 m
emf, ε = 1 V
according to Faraday's law
ε = -N dΦ/dt, Φ = B A
= - N d( B A)/dt
= - N d( B A cos ωt)/dt
= - N B A d(cos ωt)/dt
= N B A ω sin ωt
A = πr², so
ε = N B πr² ω sin ωt
where
ε = emf
N = number of coil turn
B = magnetic field
r = radius
ω = angular velocity
Φ = magnetic flux
emf maximum, sin ωt = 1. So,
ε = N B πr² ω
ω = ε/N B πr²
= 1/[(1000) (0.0005) π (0.05)²
= 254.65 rad/s
The normal force is equal in magnitude and opposite in direction to the weight of the student.
W = m · g = 60 kg · 10 m/s² = 600 N ( downward )
N = - 600 N
Answer:
B ) 600 N upward.
X = total horizontal distance = 25 ft
Y = total vertical distance = 125 ft
x = horizontal distance = 1 ft
y = vertical distance = ?
using the equation
y = (Y/X) (x)
inserting the values
y = (125/25) (1)
y = 5 ft
hence for each horizontal foot, the average height change is 5 ft
or
25 ft horizontal distance traveled = 125 ft vertical distance dropped
dividing both side by 25
25 ft horizontal distance traveled/25 = 125 ft vertical distance dropped/25
1 foot horizontal distance traveled = 25 ft vertical distance dropped