a) This refers to the mode = $575
b) This refers to the median = $581
c) This refers to the 86th Percentile = $612
d) This refers to the First Quartile = $552
e) The salary is that is 2 standard deviations below the mean = $529
f) About 36 percent of employee's salaries is above $592
g) $627 is 1.5 standard deviations above the mean
<u>Given data</u>
Mean = $585
Median = $581
Mode = $575
First Quartile = $552
Third Quartile = $605
Standard deviation = $28.
86th Percentile = $612
P64 = $592
<h3>How to find the required values</h3>
a) What is the most common salary? $575
This refers to the mode = $575
b) What salary did half the employee's salaries surpass? $581
This refers to the median = $581
c) About what percent of employee's salaries is below $612?
This refers to the 86th Percentile = $612
d) What percent of the employee's salaries are above $552?
This refers to the First Quartile = $552
e) What salary is 2 standard deviations below the mean?
The mean is given as $585 and the standard deviation is $28
2 standard deviation below the mean is:
= 585 - 2 * 28
= 585 - 56
= $529
f) About what percent of employee's salaries is above $592?
P64 is given as $592 this refers to the percent of employee's salaries that falls under 64%. so the percent above is above 64 is given as:
= 100 - 64
= 36%
g) What salary is 1.5 standard deviations above the mean?
The mean is given as $585 and the standard deviation is $28
1.5 standard deviation below the mean is:
= 585 + 1.5 * 28
= 585 + 42
= $627
Read more on standard deviation here: brainly.com/question/475676
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