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2 years ago

Approximate the distance between points -3,5 and 7,-1. 5.7 units 32 units 11.7 units 136 units

Mathematics

1 answer:

ludmilkaskok [199]2 years ago

7 0

Answer:

11.7

Step-by-step explanation:

I took the the test and this was the correct answer.

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Use the definition f ′(x) = h0f(x + h) - f(x)h to find the derivative. f(x)=x+2

NNADVOKAT [17]

Answer:

f'(x) = 1

General Formulas and Concepts:

Calculus

Limit Properties: $\lim_{n \to a} c = c$
Definition of a Derivative: $f'(x)= \lim_{h \to 0} \frac{f(x+h)-f(x)}{h}$

Step-by-step explanation:

Step 1: Define

f(x) = x + 2

Step 2: Find derivative

Substitute: $f'(x)= \lim_{h \to 0} \frac{((x + h) + 2)-(x+2)}{h}$
Distribute: $f'(x)= \lim_{h \to 0} \frac{x + h + 2-x-2}{h}$
Combine like terms: $f'(x)= \lim_{h \to 0} \frac{h}{h}$
Divide: $f'(x)= \lim_{h \to 0} 1$
Evaluate: $f'(x)= 1$

8 0

2 years ago

Which is the vertex of x^2 + 10x = - 17?

Dafna11 [192]

Answer:

(-5, -8)

Step-by-step explanation:

Parabolas always have a lowest point (or a highest point, if the parabola is upside-down). This point, where the parabola changes direction, is called the "vertex". If the quadratic is written in the form y = a(x – h)2 + k, then the vertex is the point (h, k).

x^2 + 10x = - 17

x^2+10x+17=0

x^2+2*5x+25 - 8=0

(x+5)^2-8=0

h=-5, k= -8

vertex is (-5, -8)

3 0

2 years ago

The question is in the picture

svetlana [45]

Answer:

∠CBA

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Find the area of the kite p=17 q =15.3

Semenov [28]

Answer:

$\large\boxed{A=130.05}$

Step-by-step explanation:

The formula of an area of a kite:

$A=\dfrac{pq}{2}$

p, q - diagonals

We have p = 17 and q = 15.3. Substitute:

$A=\dfrac{(17)(15.3)}{2}=\dfrac{260.1}{2}=130.05$

3 0

2 years ago

A specific distance is approximately 63,500,00 mi. A fly is about 0.18 in. long ???

wolverine [178]

Answer:

Step-by-step explanation:

a) Given that a specific distance is approximately 6350000 miles.

To write this in scientific notation. We know that for writing in scientific notation we must writte the given number as a positive number less than 10 x product of powers of n.

Hence this number

6350000 = 6.35 x1000000 = $6.35x10^6$ miles

b) Length of a fly = 0.18 inches.

To write this in scientific notation. We know that for writing in scientific notation we must writte the given number as a positive number less than 10 x product of powers of n.

so 0.18 = 1.8( $1.8(10^{-1}$

c) Given that distance = 5.04x10^9 inches

To line up number of flies required

= $\frac{5.04x10^9}{0.18} = \frac{504x10^9}{18}=28(10^9)\\Answer is\\28(10^9)$

6 0

3 years ago