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kumpel [21]
3 years ago
13

A pilot must fly his plane due north to reach his destination. The plane can fly at 300 km/h in still air. A wind is blowing out

of the northeast at 90 km/h.
(a) What is the speed of the plane relative to the ground?

(b) In what direction must the pilot head her plane to fly due north?
Physics
1 answer:
ikadub [295]3 years ago
4 0

Answer:

Answer explained below

Explanation:

The situation in this problem suggests that the pilot wants to fly the plane towards north with a velocity of magnitude 300km/hr. But the wind is flowing from Northeast with the magnitude of 90km/hr.

(a) so there's a wind resistance in action, which will prevent the plane from reaching its desired speed of 300km/hr. That means the velocity of the plane with respect to ground will be less than 300km

The plane needs to have a northward heading but the wind is forcing it towards southwest. So the pilot has to compensate for this resistance by changing the direction of the plane i.e. flying towards northeast so that the effect of the wind is nullified and plane keeps flying north at the expense of velocity . It's a simple matter of vector addition by triangle law to find out the resultant velocity as the author has explained. So the theory used by the author is correct and the math checks out to.

(b) the destination of the plane is due north. So it has to fly towards north with respect to ground. So it's velocity vector must be pointing north with respect to the ground. But the wind velocity vector is oriented from Northeast - northwest direction. i e. tail of the wind velocity vector is towards northeast and the head is towards northwest and attached to the head of the northward velocity of the plane. This northward velocity is the resultant velocity maintained by the plane by flying towards northeast at a velocity of 300km/hr. That gives us the resultant northward velocity by triangle law of vector addition to be 230km/hr.

Since we are dealing with a triangle of vectors,we can simply apply basic trigonometry to decide in what direction must the plane fly in order to maintain a northward heading. The author has used the correct relation to calculate the direction of the plane. To have a north heading,it means that the wind resistance is compensated by sacrificing some of the velocity.

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Here on Earth you hang a mass from a vertical spring and start it oscillating with amplitude 1.9 cm. You observe that it takes 3
Vlada [557]

Answer:

T = 3.23 s

Explanation:

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With the initial data let's look for the ratio k / m

The angular velocity is related to the frequency and period

           w = 2π f = 2π / T

            2π / T = √ k / m

            k₀ / m₀ = (2π / T)²

            k₀ / m₀ = (2π / 3.0)²

            k₀ / m₀ = 4.3865

The period on the new planet is

          2π / T = √ k / m

           T = 2π √ m / k

In this case the amounts are

           m = 6 m₀

           k = 10 k₀

We replace

            T = 2π√6m₀ / 10k₀

            T = 2π √6/10 √m₀ / k₀

            T = 2π √ 0.6  √1 / 4.3865

            T = 3.23 s

5 0
3 years ago
Match the lithification processes.
butalik [34]

Explanation:

Recrystallization: contact pressure causing grains to "fuse" together

Cementation : precipitation of bonding agents between grains

Compaction : increase in density due to weight of overburden

Lithification is the process by which sediments are converted into sedimentary rocks. During this process, recrystallication, compaction and cementation of mineral grains occur.

The process starts with the compaction of sediments. The over burden weight of new sediments in the basin adds to the one originally deposited. This compresses the sediment. The volume of reduced and the density increases.

Recrystallization follows suit as the contact pressure of grains makes them fuse together. It is more like reworking of sediments. In this process, cementing materials can precipitate and cause sediments to be more fused together.

This is why most sediment are made up of clasts in a matrix of cementing materials.

learn more:

sedimentary rocks brainly.com/question/9131992

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4 0
3 years ago
Write a numerical expression for the emissive intensity (in W/m^2.sr) coming out of a tiny hole in an enclosure of surface tempe
stiks02 [169]

Answer:

6.0 × 10^{11} W/m^{2}

Explanation:

From Wien's displacement formula;

Q = e AT^{4}

Where: Q is the quantity of heat transferred, e is the emissivity of the surface, A is the area, and T is the temperature.

The emissive intensity = \frac{Q}{A} = eT^{4}

Given from the question that: e = 0.6 and T = 1000K, thus;

emissive intensity = 0.6 × (1000)^{4}

                             = 0.6 × 1.0 × 10^{12}

                             = 6.0 × 10^{11} \frac{W}{m^{2} }

Therefore, the emissive intensity coming out of the surface is 6.0 × 10^{11} W/m^{2}.

3 0
3 years ago
The world's fastest production sportscar has a top speed of 415 kmh-1(a)Convert this speed to ms-1.[ 1](b)The distance from Lond
Alex73 [517]

Answer:

(a). The speed is 115.28 m/s.

(b). The time is 94 min.

(c). The International Space Station travels 43202.400 km.

(d). Speed is scalar quantity.

Velocity is vector quantity.

Explanation:

Given that,

Top speed = 415 km/h

1 miles = 1609 m

(a). We need to calculate the speed in m/s

Using conversion of km/h to m/s

v=415\ km/h

v=415\times\dfrac{5}{18}

v=115.28\ m/s

(b). We need to calculate the distance from London to Edinburgh in km

Using conversion for distance

d=403\ miles

Distance in meter,

d=403\times1609

d=648427\ m

d=648.427\ km

We need to calculate the time

Using formula of time

t=\dfrac{d}{v}

Put the value into the formula

t=\dfrac{648.427}{415}

t=1.56\ h

t=1\ hours 34\ min

t= 94\ min

(c). Speed v' =7.66 km/s

v'=7660 m/s

In the time it takes the car to travel from London to Edinburgh,

We need to calculate the distance

Using formula of distance

d'=v'\times t

Put the value into the formula

d'=7660\times94\times60

d'=43202400\ m

d'=43202.400\ km

(d). Speed :

Speed is equal to the distance divided by time.

It is scalar quantity.

Velocity :

Velocity is equal to the displacement divided by time.

It is vector quantity.

Hence, (a). The speed is 115.28 m/s.

(b). The time is 94 min.

(c). The International Space Station travels 43202.400 km.

(d). Speed is scalar quantity.

Velocity is vector quantity.

3 0
3 years ago
A 2.00-kg rock has a horizontal velocity of magnitude 12.0 m>s when it is at point P in Fig. E10.35. (a) At this instant, wha
zaharov [31]

Answer:

(A) L = 115.3kgm²/s

(B) dL/dt = 94.1kgm²/s²

Explanation:

The magnitude of the angular momentum of the rock is given by the foemula

L = mvrSinθ

We have been given θ = 36.9°, m = 2.0kg, v = 12.0m/s and r = 8.0m.

Therefore L = 2.00 × 12 × 8.0 × Sin 36.9° =

115.3 kgm²/s

(B) The magnitude of the rate of angular change in momentum is given by

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7 0
3 years ago
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