Answer:
1.38 s
Explanation:
Use the free falling formula
T = √(L)/ g
T = √18.75/9.8
T = 1.38 s
Answer:
Explanation:
Earliest standards were dependent on a single frequency/channel to both send and receive. This shared medium creates the same problem as half-duplex coax cable. Because receivers had to wait for the signal before sending a response, this reduced the overall bandwidth.
Other factors affect wireless signal propagation, too, including RF interference, antenna choice, and obstacles such as walls, trees, and even weather (precipitation, for example).
Answer:
The time taken by the car to accelerate from a speed of 24.6 m/s to a speed of 26.8 m/s is 0.84 seconds.
Explanation:
Given that,
Acceleration of the car, ![a=+2.6\ m/s^2](https://tex.z-dn.net/?f=a%3D%2B2.6%5C%20m%2Fs%5E2)
Initial speed of the car, u = 24.6 m/s
Final speed of the car, v = 26.8 m/s
We need to find the time taken by the car to accelerate from a speed of 24.6 m/s to a speed of 26.8 m/s. The acceleration of an object is given by :
![t=\dfrac{v-u}{a}](https://tex.z-dn.net/?f=t%3D%5Cdfrac%7Bv-u%7D%7Ba%7D)
![t=\dfrac{(26.8-24.6)\ m/s}{2.6\ s}](https://tex.z-dn.net/?f=t%3D%5Cdfrac%7B%2826.8-24.6%29%5C%20m%2Fs%7D%7B2.6%5C%20s%7D)
t = 0.84 seconds
So, the time taken by the car to accelerate from a speed of 24.6 m/s to a speed of 26.8 m/s is 0.84 seconds. Hence, this is the required solution.