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zaharov [31]
1 year ago
7

Options: A.) 10 N B.) 15 N C.) 25 N D.) 35N

Physics
1 answer:
Lady_Fox [76]1 year ago
7 0

Given:

F_gravity = 10 N

F_tension = 25 N

Let's find the net centripetal force exterted on the ball.

Apply the formula:

\sum ^{}_{}F_{\text{net}}=F_1+F_2=F_{centripetal}

From the given figure, the force acting towards the circular path will be positive, while the force which points directly away from the center is negative.

Hence, the tensional force is positive while the gravitational force is negative.

Thus, we have:

F_{\text{net}}=F_{\text{centripetal}}=F_{tension}-F_{gravity}=25N-10N=15N

Therefore, the net centripetal force exterted on the ball is 15 N.

ANSWER:

15 N

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Answer:

Explanation:

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coefficient of static friction, μs = 0.85

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F net = 950 - 636.02

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a = F net / mass

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The resultant force on the positive charge  is mathematically given as

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Question Parameters:

Three-point charges, two positive and one negative, each having a magnitude of 20

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Q+=\sqrt{x^2+x^2+2x.xcos120}\\\\Q+=\sqrt{2x^2+2x*(1/2)}

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For more information on Force

brainly.com/question/26115859

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