Options: A.) 10 N B.) 15 N C.) 25 N D.) 35N
1 answer:
Given:
F_gravity = 10 N
F_tension = 25 N
Let's find the net centripetal force exterted on the ball.
Apply the formula:
From the given figure, the force acting towards the circular path will be positive, while the force which points directly away from the center is negative.
Hence, the tensional force is positive while the gravitational force is negative.
Thus, we have:
Therefore, the net centripetal force exterted on the ball is 15 N.
ANSWER:
15 N
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The formula your looking for is Vf = Vi + A (T)
Vf = Velocity Final
Vi = Velocity Initial
A = Acceleration
T = Time
Our Initial Velocity is 15m/s. That’s our starting point.
Acceleration is -3m/s. It’s negative because we’re slowing down
We know that the cyclist comes to a complete stop, which means the Final Velocity is 0
In order to solve this with the equation. We need three of the four variables. We just don’t know time. So our setup is -
0 = 15-3(T)
Then you solve
Vf = Velocity Final
Vi = Velocity Initial
A = Acceleration
T = Time
Our Initial Velocity is 15m/s. That’s our starting point.
Acceleration is -3m/s. It’s negative because we’re slowing down
We know that the cyclist comes to a complete stop, which means the Final Velocity is 0
In order to solve this with the equation. We need three of the four variables. We just don’t know time. So our setup is -
0 = 15-3(T)
Then you solve