<span> an analytical method used to separate colored chemicals or substances.</span>
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Answer:
19 years
Explanation:
Tritium follows a first-order decay which can be represented by the following expression.
![ln(\frac{[H]_{t}}{[H]_{0}} )=-k.t](https://tex.z-dn.net/?f=ln%28%5Cfrac%7B%5BH%5D_%7Bt%7D%7D%7B%5BH%5D_%7B0%7D%7D%20%29%3D-k.t)
where,
[H]t is the concentration of tritium at a certain time t
[H]₀ is the initial concentration of tritium
k is the rate constant
If we know the half-life (t1/2), we can calculate the rate constant.
![k=\frac{ln2}{t_{1/2}} =\frac{ln2}{12.3y} =0.0564y^{-1}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7Bln2%7D%7Bt_%7B1%2F2%7D%7D%20%3D%5Cfrac%7Bln2%7D%7B12.3y%7D%20%3D0.0564y%5E%7B-1%7D)
![ln(\frac{[H]_{t}}{[H]_{0}} )=-k.t\\ln(\frac{0.34[H]_{0}}{[H]_{0}} )=-(0.0564y^{-1}).t\\t=19y](https://tex.z-dn.net/?f=ln%28%5Cfrac%7B%5BH%5D_%7Bt%7D%7D%7B%5BH%5D_%7B0%7D%7D%20%29%3D-k.t%5C%5Cln%28%5Cfrac%7B0.34%5BH%5D_%7B0%7D%7D%7B%5BH%5D_%7B0%7D%7D%20%29%3D-%280.0564y%5E%7B-1%7D%29.t%5C%5Ct%3D19y)