I guess you could call them that. In chemistry, we call them Metalloids though.
Answer:
12.44 g
Explanation:
2C4H10 + 13O2 = 8CO2 + 10H2O
n(C4H10) = m(C4H10)/M(C4H10) = 4.1 / 58g/mol = 0.0707 mol (excess).
n(O2) = m(O2)/M(O2) = 25.9 / 32g/mol = 0.809 mol (deficiency).
Since the ratio of O2 to octane is 13 : 2 we can divide 0.0707 by 2 to get 0.03535 and divide 0.809 by 13 to get 0.062.
mass of CO2 produced =
M = [0.0707 moles C4H10 x 8 moles CO2] / 2 moles C4H10 x 44 g CO2/mol
M = 0.5656/2 * 44
M = 0.2828 * 44
M = 12.44 of CO2
High conductivity of metals is caused by electrons that are free to move through the lattice.
hope this helps!
Answer:try to make a good pic please I have ideas about the topic
Answer:
OCO
Another way of writing CO₂
Explanation:
A reaction equation has <u>reactants on the left</u> and <u>products on the right</u>.
The reactants are carbon and oxygen. The product is carbon dioxide.
C + O₂ → CO₂
You might see the equation both ways.
C + O₂ → OCO
C + O₂ in the products would mean no reaction has occurred. The problem can <u>solid carbon can burn in oxygen</u>, so a reaction will occur. For no reaction, you would put "NR" in the products.
<u>OCO is the structural way of writing CO₂.</u> Both have one carbon atom (C) and two oxygen atoms (O).
C + 2O is not possible. Oxygen, if alone, has to be at least O₂ because it's a <u>diatomic molecule</u>.
