Answer:
Explanation:
Initial angular velocity ω₀ = 151 x 2π / 60
= 15.8 rad /s
final velocity = 0
Angular deceleration α = 2.23 rad / s
ω² = ω₀² - 2 α θ
0 = 15.8² - 2 x 2.23 θ
= 55.99 rad
one revolution = 2π radian
55.99 radian = 55.99 / 2 π no of terns
= 9 approx .
<h2>
Right answer: 64 units</h2><h2>
</h2>
According to the law of universal gravitation, which is a classical physical law that describes the gravitational interaction between different bodies with mass:

Where:
is the module of the force exerted between both bodies
is the universal gravitation constant.
and
are the masses of both bodies.
is the distance between both bodies
In this case we have a gravitation force
, given by the formula written at the beginning. Let’s rename the distance
as
:
(1)
And we are asked to find the gravitation force
with a given distance of
:
(2)
The gravity constant is the same for both equations, and we are assuming both masses are constants, as well. So, let’s isolate
in both equations:
From (1):
(3)
From (2):
(4)
If (3)=(4):
(5)
Now we have to find
:
(6)
If
:
>>>>This is the new force of attraction
Answer:
13.4 m/s
Explanation:
Write down what you have, so:
V0=8 m/s
a=2.7 m/s^2
t=2 seconds
We are trying to find final velocity, so we will use vf = v0 + at
From there, we plug in the given values.
vf = 8 m/s + (2.7 m/s^2 x 2 seconds)
vf = 13.4 m/s