1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vilka [71]
3 years ago
11

Mosses don't spread by dispersing seeds; they disperse tiny spores. The spores are so small that they will stay aloft and move w

ith the wind, but getting them to be windborne requires the moss to shoot the spores upward. Some species do this by using a spore-containing capsule that dries out and shrinks. The pressure of the air trapped inside the capsule increases. At a certain point, the capsule pops, and a stream of spores is ejected upward at 3.6 m/s, reaching an ultimate height of 20 cm.A)What fraction of the initial kinetic energy is converted to the final potential energy?Express your answer numerically.UfKi =B)What happens to the "lost" energy?Choose the correct answerIt has been transformed into thermal energy of the spores and surrounding air.It has been transformed into thermal energy of the spores and potential energy of surrounding air.It has been transformed into potential energy of the spores and kinetic energy of surrounding air.It has been transformed into potential energy of the spores and surrounding air.
Physics
1 answer:
AnnyKZ [126]3 years ago
3 0

A) 0.3

The initial kinetic energy of the stream of spores is

K_i = \frac{1}{2}mv^2

where m is the mass of the spores and v = 3.6 m/s is their initial speed.

The final gravitational potential energy (at the point of maximum height) of the spores is

U_f = mgh

where g=9.8 m/s^2 is the acceleration due to gravity and h = 20 cm = 0.20 m is the maximum height.

Therefore, the fraction of kinetic energy converted to final potential energy is

\frac{U_f}{K_i}=\frac{mgh}{\frac{1}{2}mv^2}=\frac{2gh}{v^2}=\frac{2(9.8 m/s^2)(0.20 m)}{(3.6 m/s)^2}=0.30

So, about 30% of the initial kinetic energy is converted into potential energy.

B) It has been transformed into thermal energy of the spores and surrounding air

In fact, because of the presence of the air resistance during the motion of the spores, some of the mechanical energy of the spores is "wasted" and converted into thermal energy (heat) of the spores and the surrounding air. Without the air resistance, the mechanical energy would be conserved, and the final potential energy of the spore would be equal to the initial kinetic energy.

You might be interested in
Technician A says that LCDs may be slow to work at low temperatures. Technician B says that an LCD dash display can be damaged i
never [62]

Answer:

c

Explanation:

6 0
3 years ago
An electric motor rotating a workshop grinding wheel at a rate of 151 rev/min is switched off. Assume constant angular decelerat
tamaranim1 [39]

Answer:

Explanation:

Initial angular velocity ω₀ = 151 x 2π / 60

= 15.8  rad /s

final velocity = 0

Angular deceleration α = 2.23 rad / s

ω² = ω₀² -  2 α θ

0 = 15.8² - 2 x 2.23 θ

= 55.99  rad

one revolution = 2π radian

55.99 radian = 55.99  / 2 π no of terns

= 9 approx .

8 0
3 years ago
Can someone help meeeeee... show how to solve it plzzzzzzzz
liubo4ka [24]
<h2>Right answer: 64 units</h2><h2></h2>

According to the law of universal gravitation, which is a classical physical law that describes the gravitational interaction between different bodies with mass:

F=G\frac{m_{1}m_{2}}{r^2}

Where:

F is the module of the force exerted between both bodies

G is the universal gravitation constant.

m_{1} and m_{2} are the masses of both bodies.

r is the distance between both bodies

In this case we have a gravitation force F_{1}=16units, given by the formula written at the beginning. Let’s rename the distance r as d:

F_{1}=G\frac{m_{1}m_{2}}{d^2}     (1)

And we are asked to find the gravitation force F_{2} with a given distance of \frac{d}{2}:

F_{2}=G\frac{m_{1}m_{2}}{({\frac{d}{2})}^{2}}      

F_{2}=G\frac{m_{1}m_{2}}{{\frac{d^{2}}{4}}}     (2)

The gravity constant is the same for both equations, and we are assuming both masses are constants, as well. So, let’s isolate G m_{1}m_{2} in both equations:

From (1):

Gm_{1}m_{2}=F_{1}{d}^{2}     (3)

From (2):

Gm_{1}m_{2}=F_{2}\frac{{d}^{2}}{4}     (4)

If (3)=(4):

F_{1}{d}^{2}=F_{2}\frac{{d}^{2}}{4}     (5)

Now we have to find F_{2}:

F_{2}=F_{1}{d}^{2}\frac{4}{{d}^{2}}      

F_{2}=4F_{1}     (6)

If F_{1}=16 units:

F_{2}=(4)(16 units)        

F_{2}=64 units>>>>This is the new force of attraction     

3 0
3 years ago
A student eats a candy bar that contains 1.57 x 106 J of energy. If the student has a mass of 81.8 kg, how high will he have to
gogolik [260]

Answer:abb

Explanation:bsjsnd

6 0
3 years ago
May I please get some help?
morpeh [17]

Answer:

13.4 m/s

Explanation:

Write down what you have, so:

V0=8 m/s

a=2.7 m/s^2

t=2 seconds

We are trying to find final velocity, so we will use vf = v0 + at

From there, we plug in the given values.

vf = 8 m/s + (2.7 m/s^2 x 2 seconds)

vf = 13.4 m/s

5 0
4 years ago
Read 2 more answers
Other questions:
  • How could you keep an object's acceleration the same if the force acting on the object were doubled?
    5·2 answers
  • Which two types of simple machines can be found in a bicycle? lever and wheel and axle pulley and wedge wedge and wheel and axle
    14·2 answers
  • A child drops a ball from a window. The ball strikes the ground in 3.0 seconds. What is the velocity of the ball the instant bef
    15·1 answer
  • A circular coil of wire of 200 turns and diameter 6 cm carries a current of 7 A. It is placed in a magnetic field of 0.90 T with
    11·1 answer
  • How does what happens to the particles in a substance during melting differ from what happens during freezing?
    6·1 answer
  • Suppose a particle moves back and forth along a straight line with velocity v(t), measured in feet per second, and acceleration
    13·1 answer
  • Can someone help me with this
    6·2 answers
  • Un automóvil que va a 36Km/h acelera durante 8segundos hasta llegar a una velocidad de 108 Km/h y luego frena hasta detenerse en
    9·1 answer
  • A wooden block is let go from a height of 5.80 m. What is the velocity of the block just before it hits the ground?
    10·1 answer
  • A 20 kg mass is hanging on one side of a pulley and a 5 kg mass is hanging on the other. Determine the acceleration of each mass
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!