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3 years ago

How could you keep an object's acceleration the same if the force acting on the object were doubled?

2 answers:

7 0

If the force on an object suddenly doubles, but for some reason you want
the object to keep the same acceleration, then you have only two choices:

#1). Immediately apply another new force to the object, in the direction opposite
to the first force, and equal to what the first force was before it doubled.

#2). Somehow ... while it's accelerating ... glue more pieces onto the object
sufficient to double its mass.

vazorg [7]3 years ago

6 0

$Force=mass*acceleration$
If you double the force, but want to keep acceleration the same, then you must double the mass as well.
$Force=mass*acceleration \\ (2)Force=(2)mass*acceleration$

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2 years ago

A 5kg bag falls a verticle height of 10m before hitting the ground.

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Answer:

$u = 7m {s}^{ - 1}$

Explanation:

We know that when we don't have air friction on a free fall the mechanical energy (I will symbololize it with ME) is equal everywhere. So we have:

$me(1) = me(2)$

where me(1) is mechanical energy while on h=10m

and me(2) is mechanical energy while on the ground

Ek(1) + DynamicE(1) = Ek(2) + DynamicE(2)

Ek(1) is equal to zero since an object that has reached its max height has a speed equal to zero.

DynamicE(2) is equal to zero since it's touching the ground

Using that info we have

$m \times g \times h = \frac{1}{2} \times m \times u {}^{2} \\$

we divide both sides of the equation with mass to make the math easier.

$9.8 \times 10 = \frac{1}{2} \times u {}^{2} \\ \frac{98}{2} = u {}^{2} \\ u { }^{2} = 49 \\ u = 7$

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3 years ago

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$v = \sqrt{\frac{T}{\mu}}$