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stepan [7]
3 years ago
5

How could you keep an object's acceleration the same if the force acting on the object were doubled?

Physics
2 answers:
kykrilka [37]3 years ago
7 0

If the force on an object suddenly doubles, but for some reason you want
the object to keep the same acceleration, then you have only two choices:

#1). Immediately apply another new force to the object, in the direction opposite
to the first force, and equal to what the first force was before it doubled.

#2).  Somehow ... while it's accelerating ... glue more pieces onto the object
sufficient to double its mass.


vazorg [7]3 years ago
6 0
Force=mass*acceleration
If you double the force, but want to keep acceleration the same, then you must double the mass as well.
Force=mass*acceleration  \\ (2)Force=(2)mass*acceleration
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Magnesium is a shiny, flexible metal that can be burned in the presence of air.
alukav5142 [94]

Answer:

A new substance was formed

Explanation:

According to this question, a shiny and flexible metal called Magnesium (Mg) is burnt in air to produce a white powder that has no shiny or flexible properties, however, has more weight than the magnesium metal itself.

This is possible because a CHEMICAL CHANGE has occured, hence, a new substance has been formed. The formation of a new substance during the burning process (chemical reaction), induced the increase in mass.

8 0
2 years ago
Which types of geometrical symmetry does a sphere have?.
Helen [10]
A sphere has reflection symmetry across any plane through its center.
8 0
2 years ago
A shell is fired with a horizontal velocity in the positive x direction from the top of an 80 m high cliff. The shell strikes th
Sonbull [250]

Answer:

V = 331.59m/s

Explanation:

First we need to calculate the time taken for the shell fire to hit the ground using the equation of motion.

S = ut + 1/2at²

Given height of the cliff S = 80m

initial velocity u = 0m/s²

a = g = 9.81m/s²

Substitute

80 = 0+1/2(9.81)t²

80 = 4.905t²

t² = 80/4.905

t² = 16.31

t = √16.31

t = 4.04s

Next is to get the vertical velocity

Vy = u + gt

Vy = 0+(9.81)(4.04)

Vy = 39.6324

Also calculate the horizontal velocity

Vx = 1330/4.04

Vx = 329.21m/s

Find the magnitude of the velocity to calculate speed of the shell as it hits the ground.

V² = Vx²+Vy²

V² = 329.21²+39.63²

V² = 329.21²+39.63²

V² = 108,379.2241+1,570.5369

V² = 109,949.761

V = √ 109,949.761

V = 331.59m/s

Hence the speed of the shell as it hits the ground is 331.59m/s

7 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
mestny [16]
C standards are based on observable, reproducible natural phenomena.
3 0
3 years ago
Looking at the position of the house and the tree, if the man ran starting from the house going
Aleks04 [339]

Average velocity of man is 2 m/s

<u>Given that;</u>

Distance between tree and house = 16 m

Time taken = 8 seconds

<u>Find:</u>

Average<em> velocity</em>

<u>Computation:</u>

Average velocity = Total distance cover / Time taken

Average velocity = Distance between tree and house / Time taken

Average velocity = 16 / 8

Average velocity = 2 m/s

Learn more:

brainly.com/question/22610586?referrer=searchResults

4 0
2 years ago
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