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3 years ago

How could you keep an object's acceleration the same if the force acting on the object were doubled?

2 answers:

7 0

If the force on an object suddenly doubles, but for some reason you want
the object to keep the same acceleration, then you have only two choices:

#1). Immediately apply another new force to the object, in the direction opposite
to the first force, and equal to what the first force was before it doubled.

#2). Somehow ... while it's accelerating ... glue more pieces onto the object
sufficient to double its mass.

vazorg [7]3 years ago

6 0

$Force=mass*acceleration$
If you double the force, but want to keep acceleration the same, then you must double the mass as well.
$Force=mass*acceleration \\ (2)Force=(2)mass*acceleration$

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A train that travel 100 kilometer in 4hours is traveling at what speed?

DochEvi [55]

Speed = Distance/Time = 100 km / 4 hours = 100/4 km per hour = 25 kph

5 0

3 years ago

If the wavelength of light in the visible region is known, what is also known? check all that apply. question 4 options:

maw [93]

If the wavelength of light in the visible region is known, it is also known as frequency.

<h3>What is frequency?</h3>

Recurrence is the quantity of events of a rehashing occasion for every unit of time. It is likewise once in a while alluded to as worldly recurrence to underline the differentiation to spatial recurrence, and customary recurrence to underscore the difference to rakish recurrence. Rotating current (ac) recurrence is the quantity of cycles each second in an air conditioner sine wave. Recurrence is the rate at which current heads in a different path each second. It is estimated in hertz (Hz), a global unit of measure where 1 hertz is equivalent to 1 cycle each second. It is likewise infrequently alluded to as transient recurrence to stress the difference to spatial recurrence, and normal recurrence to accentuate the differentiation to precise recurrence. Recurrence is estimated in hertz (Hz) which is equivalent to one occasion each second.

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7 0

1 year ago

What is the internal energy of 2.00 mol of diatomic hydrogen gas (H2) at 35°C?

djyliett [7]

As you mentioned, we will use <span>Equipartition Theorem.
</span><span>H2 has 5 degrees of freedom; 3 translations and 2 rotation
</span>Therefore:
Internal energy = (5/2) nRT
You just substitute in the equation with the values of R and T and calculate the internal energy as follows:
Internal energy = (5/2) x 2 x <span>8.314 x 308 = 32.0089 x 10^3 J</span>

4 0

2 years ago

A spherical, conducting shell of inner radius r1= 10 cm and outer radius r2 = 15 cm carries a total charge Q = 15 μC . What is t

lutik1710 [3]

a) E = 0

b) $3.38\cdot 10^6 N/C$

Explanation:

We can solve this problem using Gauss theorem: the electric flux through a Gaussian surface of radius r must be equal to the charge contained by the sphere divided by the vacuum permittivity:

$\int EdS=\frac{q}{\epsilon_0}$

where

E is the electric field

q is the charge contained by the Gaussian surface

$\epsilon_0$ is the vacuum permittivity

Here we want to find the electric field at a distance of

r = 12 cm = 0.12 m

Here we are between the inner radius and the outer radius of the shell:

$r_1 = 10 cm\\r_2 = 15 cm$

However, we notice that the shell is conducting: this means that the charge inside the conductor will distribute over its outer surface.

This means that a Gaussian surface of radius r = 12 cm, which is smaller than the outer radius of the shell, will contain zero net charge:

q = 0

Therefore, the magnitude of the electric field is also zero:

E = 0

Here we want to find the magnitude of the electric field at a distance of

r = 20 cm = 0.20 m

from the centre of the shell.

Outside the outer surface of the shell, the electric field is equivalent to that produced by a single-point charge of same magnitude Q concentrated at the centre of the shell.

Therefore, it is given by:

$E=\frac{Q}{4\pi \epsilon_0 r^2}$