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4 years ago

How could you keep an object's acceleration the same if the force acting on the object were doubled?

2 answers:

7 0

If the force on an object suddenly doubles, but for some reason you want
the object to keep the same acceleration, then you have only two choices:

#1). Immediately apply another new force to the object, in the direction opposite
to the first force, and equal to what the first force was before it doubled.

#2). Somehow ... while it's accelerating ... glue more pieces onto the object
sufficient to double its mass.

vazorg [7]4 years ago

6 0

$Force=mass*acceleration$
If you double the force, but want to keep acceleration the same, then you must double the mass as well.
$Force=mass*acceleration \\ (2)Force=(2)mass*acceleration$

You might be interested in

A population has a birthrate of 10/1000 , a death rate of 9/1000, an immigration rate of 3/1000, and an emigration rate of 7/100

Charra [1.4K]

Birth rate 10/1000 = +population

Death rate 9/1000 = -population

Immigration rate 3/1000 = +population

Emigration rate 7/1000 = -population

10/1000 - 9/1000 + 3/1000 - 7/1000= -3/1000

Growth rate = (-3/1000)(100%)= -0.3%

3 0

4 years ago

The equation of a wave is represented by: Y = 0.005sin 2π(0.5x – 200t) where x and y are in meters and t in seconds. Find its i.

lys-0071 [83]

Answer:

See solution below

Explanation:

The standard equation of a wave is represented by: Y = Asin 2π(x/λ – ft)

A is the amplitude

λ is the wavelength

f is the frequency

t is the time

Comparing the standard with the given equation Y = 0.005sin 2π(0.5x – 200t)

i) A = 0.005m

Amplitude is 0.005m

ii) ω = 2πf

ω = 2π(200)

ω = 400π rad/s

iii) ω = 2πf

400π = 2πf

200 = f

Swap

f = 200Hertz

iv) Period = 1/f

Period = 1/200

Period = 0.005secs

v) wave number =

vi) Wavelength λ

0.5x = x/λ

0.5 = 1/λ

λ = 1/0.5

λ = 2m

vii) velocity - fλ

velocity = 200 * 2

velocity = 400m/s

7 0

3 years ago

14. Which of the following accurately describes the differences between the SI and English systems of measurement?

nasty-shy [4]

Answer:

B. The English system is preferred for use in the scientific and technical communities due to its ease of us of the SI system

Explanation:

This is true due to the the fact that in the English system, all you have to do to change from one measurement to the other is just move the decimal place. For example: I have 10 kg of apples and wish to convert it into grams, kilo means 1000 and grams are the base, meaning one, so we will move the decimal place to the right three places (to add the three zeros for 1,000) and the answer will 10,000. Hope you read through this and somewhat get what I mean.

5 0

3 years ago

Aerosol cans use compressed gases to propel the contents out of the can. Which of the following is the best explanation for why

vovangra [49]

Answer:

As the can heats, the compressed gases will expand, causing the can to explode

Explanation:

We know that the gases in the aerosol can would assume the shape and volume of the can. The volume of the can would be the volume of the compressed gas.

As heat is added to the can, the aerosol gases would gain kinetic energy and their speed would increase. The gases would begin to expand and would require more space in order to move. This would indirectly increase the pressures between gas molecules and the walls of the can as collisions soars.

A point would eventually be reached where the gas agitation would lead to an explosion.

Overheated aerosol cans would explode.

5 0

4 years ago

Can someone explain with the Answers pls?

Dovator [93]

Answer:

a) The frequency of the third harmonic is 786 Hz

b) The frequency of the first harmonic is 340 Hz

c) The frequency of the fifth harmonic is 1640 Hz

Explanation:

The rule is as follows:

If the first harmonic frequency (also called the fundamental frequency) is F, then:

The frequency of the second harmonic (also called the second overtone) is:

2*F

The frequency of the third harmonic (also called the third overtone) is:

3*F

And so on.

With this information, we can answer the questions:

a) We want to find the frequency of the third harmonic, such that the frequency of the first harmonic is 262 Hz.

Then we have F = 262Hz

And the frequency of the third harmonic will be:

3*F = 3*262Hz = 786 Hz

b) First harmonic for a string whose fifth harmonic frequency is 1700Hz.

Let's define F as the first frequency (the one we want to find)

Then the fifth harmonic frequency can be written as:

5*F = 1700Hz

With this equation we can find the value of F:

F = 1700Hz/5 = 340Hz

c) We want to find the fifth harmonic for a string whose third overtone (this is the same as the third harmonic) frequency is 984 Hz.

Then if the frequency of the first harmonic is F, we know that:

3*F = 984 Hz

With this we can find the value of F:

F = 984 Hz/3 =328 Hz

Now that we know the frequency of the first harmonic, we can find the frequency of the fifth harmonic:

5*F = 5*328 Hz = 1640 Hz

8 0

3 years ago