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3 years ago

A wooden block is let go from a height of 5.80 m. What is the velocity of the block just before it hits the ground?

Physics

1 answer:

Shalnov [3]3 years ago

3 0

Given :

A wooden block is let go from a height of 5.80 m.

To Find :

The velocity of the block just before it hits the ground.

Solution :

We know, by equation of motion :

$v^2 - u^2 = 2as$

Here, a = g = 9.8 m/s²( Acceleration due to gravity )

Putting all given values in above equation, we get :

$v^2 - u^2 = 2as\\\\v^2 -0 = 2\times 9.8 \times 5.8 \\\\v = \sqrt{2\times 9.8 \times 5.8 } \ m/s\\\\v = 10.66\ m/s$

Hence, this is the required solution.

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Neglect air resistance, vertically speaking, gravitational acceleration g = -9.8m/s2 is the only thing that affects water motion. We can find the time t that it takes to reach the blaze 10m above ground level

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$4.9t^2 - 19.97t + 10 = 0$

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We have 2 solutions for t, one is 0.58 when it first reach the blaze during the 1st shoot up, the other is 3.49s when it falls down

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Answer:

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