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3 years ago

8

Displacement vectors of 4 km north, 2km south, 5km north , 5km south combine a total displacement of A 2km south B16 km south C1

6 km northD 2 km north

1 answer:

Ivahew [28]3 years ago

4 0

The answer your looking for is C

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A tennis ball is released from a height of 4.0 m above the floor. After its third bounce off the floor, it reaches a height of 1

diamong [38]

Answer:

The percentage of its mechanical energy does the ball lose with each bounce is 23 %

Explanation:

Given data,

The tennis ball is released from the height, h = 4 m

After the third bounce it reaches height, h' = 183 cm

= 1.83 m

The total mechanical energy of the ball is equal to its maximum P.E

E = mgh

= 4 mg

At height h', the P.E becomes

E' = mgh'

= 1.83 mg

The percentage of change in energy the ball retains to its original energy,

$\Delta E\%=\frac{1.83mg}{4mg}\times100\%$

ΔE % = 45 %

The ball retains only the 45% of its original energy after 3 bounces.

Therefore, the energy retains in each bounce is

∛ (0.45) = 0.77

The ball retains only the 77% of its original energy.

The energy lost to the floor is,

E = 100 - 77

= 23 %

Hence, the percentage of its mechanical energy does the ball lose with each bounce is 23 %

5 0

4 years ago

A potter’s wheel of radius 17 cm starts from rest and rotates with constant angular acceleration until at the end of 32 s it is

dedylja [7]

Answer:

α=0.625rad/s^2

v=340m/s

w=10rad/s

θ=320rad

Explanation:

Constant angular acceleration = ∆w/∆t

angular acceleration = 20/32

α=0.625rad/s^2

Linear velocity v=wr

v = 20×17= 340m/s

Average angular velocity

w0+w1/2

w= 0+20/2

w= 20/2

w=10rad/s

What angle did it rotate with

θ=wt

θ= 10×32

=320rad

4 0

3 years ago

Two charges are located in the xx – yy plane. If ????1=−4.25 nCq1=−4.25 nC and is located at (x=0.00 m,y=1.080 m)(x=0.00 m,y=1.0

Sati [7]

Answer:

Ex= -17.1 N/C

Ey = +26.9 N/C

Explanation:

We apply formula of electric field:

Ep=k*q/d²

Ep: Electric field at point ( N/C)

q: Electric charge (C)

k: coulomb constant (N.m²/C²)

d: distance from charge q to point P (m)

In the attached graph we observe the directions of the electric field at P(0,0) due to q1 and q2

Calculation of the field at point P due to the load q₁

E₁=k*q₁/d₁² = 9*10⁹*4.25*10⁻⁹/1.080²= 32.8 N/C : Magnitude of E1

Direction of E₁ :Because the charge q₁ is negative the field enters the charge (+ y)

Calculation of the field at point P due to the load q₂

$d_{2} = \sqrt{1.30^{2}+0.450^{2} }$

d₂=1.375 m

E₂=k*q₂/d₂² = 9*10⁹*3.80*10⁻⁹/ 1.375² = 18.09 N/C Magnitude of E₂

Direction of E₂ :Because the charge q₂ is positive the field leaves the charge in direction of angle β

, then,E₂ tiene componentes x-y en P.

E₂x=-E₂cos β= -18.09*(1.3/1.375)= -17.1 N/C

E₂y=-E₂sin β= -18.09*(0.45/1.375)= -5.9 N/C

Calculation of the electric field at point P located at the origin(0,0)

Ex=E₂x= -17.1 N/C

Ey=E₁y+E₂y =32.8 N/C -5.9 N/C = 26.9 N/C

4 0

3 years ago

An example of a land feature formed by river erosion is?

KatRina [158]

<span>There are various examples of land features formed by river erosion. One of them is Delta. A delta is formed when sediments are deposited in a place where a river flow into an ocean or lake and build up a land form. Thus, a river delta is a land form that occurs as a result of deposition of sediments carried by a river as the flow leaves its mouth and enter a slow moving or stagnant water.</span>

7 0

3 years ago

Would you expect to weigh more on an ocean beach or on top of a mountain? Explain.

frosja888 [35]

Answer:

An Ocean beach

Explanation:

a Ocean beach is far heavier than the top of a mountain, despite that a mountain is made with many heavy rocks a Ocean beach may have light sand but the layers of sand and the width would be way heavier then the top of a mountain.

7 0

3 years ago