<h3><u>
Full question:</u></h3>
Which statements describe the Mercalli scale? Check all that apply.
A. This scale measures seismic waves based on their size.
B. This scale rates an earthquake according to how much damage it causes.
C.This scale produces a single rating for earthquakes that reach the surface.
D. This scale uses Roman numerals to rank the damage caused by an earthquake.
E.This scale measures the magnitude of an earthquake based on the size of seismic waves.
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Answer:</u></h3>
The Mercalli scale : This scale rates an earthquake according to how much damage it causes and This scale uses Roman numerals to rank the damage caused by an earthquake.
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Explanation:</u></h3>
The Modified Mercalli scale is intended to illustrate the consequences of an earthquake, at a contracted station, on tangible characteristics, on modern fittings and human beings.
The Modified Mercalli Intensity value ascribed to a particular site subsequent an earthquake has an extra significant means of severity to the nonscientist than the magnitude because intensity assigns to the outcomes really encountered at that position. This scale is comprised of 12 growing levels of intensity, denoted by Roman numerals, arranging from gradual shaking to catastrophic impairment.
A system is a regularly interacting or interdependent group of units forming an integrated whole. Every system is delineated by its spatial and temporal boundaries, surrounded and influenced by its environment, described by its structure and purpose and expressed in its functioning
Answer:
Got it from g00gle: Similarly, electrons flow more easily through a thick wire than they flow through a thin wire of the same material. Resistance is greater in a longer wire because the charges travel farther. As temperature increases, a metal's resistance increases because electrons collide more often.
Explanation:
Answer:
As per Coulomb's law we know that force between two charges is given as
F = \frac{kq_1q_2}{r^2}F=
r
2
kq
1
q
2
here we know that
q_1 = 2.5 \times 10^{-6} Cq
1
=2.5×10
−6
C
q_2 = -5.0 \times 10^{-6} Cq
2
=−5.0×10
−6
C
r = 0.0050 mr=0.0050m
now from above formula we will have
F = \frac{(9 \times 10^9)(2.5 \times 10^{-6})(5 \times 10^{-6})}{(0.0050)^2}F=
(0.0050)
2
(9×10
9
)(2.5×10
−6
)(5×10
−6
)
F = 4500 NF=4500N
so they will attract towards each other as they are opposite in nature with force F = 4500 N
