<h2>
Answer:</h2>
100.0N
<h2>
Explanation:</h2>
As the ball moves round the circle, a centripetal acceleration which is directed towards the center of the circle will keep the ball from falling off. This acceleration produces a force called centripetal force (F).
Since this is the only force acting on the ball, then the net force acting on the ball to keep it moving round the circle is the centripetal force.
F = m a [according to Newton's second law of motion] --------------(i)
<em>Where;</em>
m = mass of the ball.
a = centripetal acceleration. =
v = speed of the ball.
r = radius of the circle.
<em>Substitute a = </em><em> into equation (i) as follows;</em>
F = m x --------------------(ii)
<em>From the question;</em>
m = 2.0kg
v = 5.0m/s
r = diameter / 2 [diameter = 1.0m]
r = 1.0 / 2
r = 0.5m
<em>Substitute these values into equation (ii) as follows;</em>
F = 2.0 x
F = 2.0 x
F = 2.0 x 50.0
F = 100.0N
Therefore, the magnitude of the net force on the ball is 100.0N