1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
bija089 [108]
3 years ago
7

Scientists want to place a telescope on the moon to improve their view of distant planets. The telescope weighs 200 pounds on Ea

rth. What will happen to the weight of the telescope when it reaches the moon? The weight of the telescope will increase. The weight of the telescope will decrease. The weight of the telescope will stay the same. The weight of the telescope will be equal to its mass.
Physics
1 answer:
LuckyWell [14K]3 years ago
6 0

Answer:

Explanation:

the weight of the telescope decreases  because the moon attract the body with less force as compared to earth due to less gravity as compared to earth

You might be interested in
An astronomer is observing a star which puzzles her. The lines in the star's spectrum indicates that the star is very hot and sh
Firlakuza [10]

Answer:

the stars which are red in color are cool.

Explanation:

The stars which has reddish color are cool in nature while those stars which has white and blue in color are very hot in nature. The stars change its color when they becomes hotter , first the star color reddish when they are cool but with increasing temperature it changes the color from reddish to orange then yellow. After yellow it turns green and finally get blue color when the stars are very very hot.

5 0
3 years ago
Two black holes (the remains of exploded stars), separated by a distance of
jolli1 [7]

The largest mass is 4.7 x 10³⁰ kg and the smallest mass is 5 x 10²⁹ kg.

The given parameters;

  • <em>distance between the two black holes, r = 10 AU = 1.5 x 10¹² m</em>
  • <em>gravitational force between the two black holes, F = 6.9 x 10²⁵ N.</em>
  • <em>combined mass of the two black holes = 5.20 x 10³⁰ kg</em>

The product of the two masses is calculated from Newton's law of universal gravitational as follows;

F = \frac{Gm_1m_2}{r^2} \\\\m_1m_2 = \frac{Fr^2}{G} \\\\m_1m_2 = \frac{(6.9\times 10^{25}) \times (1.5\times 10^{12})^2}{6.67\times 10^{-11}} \\\\m_1m_2 = 2.328 \times 10^{60} \ kg^2

The sum of the two masses is given as;

m₁ + m₂ = 5.2 x 10³⁰ kg

m₂ = 5.2 x 10³⁰ kg - m₁

The first mass is calculated as follows;

m₁(5.2 x 10³⁰ - m₁) = 2.328 x 10⁶⁰

5.2 x 10³⁰m₁ - m₁² = 2.328 x 10⁶⁰

m₁² - 5.2 x 10³⁰m₁  + 2.328 x 10⁶⁰ = 0

<em>solve the quadratic equation using formula method</em>;

a = 1, b =-  5.2 x 10³⁰, c = 2.328 x 10⁶⁰

m_1 = \frac{-b \ \ +/- \ \ \sqrt{b^2 - 4ac} }{2a} \\\\m_1 = \frac{-(-5.2\times 10^{20})  \ \ +/- \ \ \sqrt{(-5.2\times 10^{20})^2 - 4(1\times 2.328\times 10^{60})} }{2(1)} \\\\m_1 = 4.7 \times 10^{30} \ kg \ \ or \ \ 4.9 \times 10^{29} \ kg

The second mass is calculated as follows;

m₂ = 5.2 x 10³⁰ kg - m₁

m₂ = 5.2 x 10³⁰ kg  -  4.7 x 10³⁰ kg

m₂ = 5 x 10²⁹ kg

or

m₂ = 5.2 x 10³⁰ kg  -  4.9 x 10²⁹ kg

m₂ = 4.7 x 10³⁰ kg

Thus, the largest mass is 4.7 x 10³⁰ kg and the smallest mass is 5 x 10²⁹ kg.

Learn more here:brainly.com/question/9373839

3 0
2 years ago
The greater the surface area of a piece of fission material, the
oksian1 [2.3K]
The answer would be b
7 0
3 years ago
A spring is originally 0.4m. When a 23N force is applied it stretches to a total of 0.7m. How far is the spring been extended? W
sergejj [24]

Recall the force applied to a spring and its extension/compression:

F = kΔx

Δx is the change in the spring's length (measured from its original length).

x = 0.7 m

x₀ = 0.4 m

Δx = x-x₀ = 0.7 m - 0.4 m = 0.3 m

F = 23 N


Substitute and solve for k:

23 = k×0.3

<h3>k = 7.67 N/m</h3>
8 0
2 years ago
As a student in a physics lab, you are asked to classify two springs. Right away you notice some differences. The first spring,
strojnjashka [21]

Answer:

C. The spring constant of spring 2 is larger than spring 1.

Explanation:

As we know that spring constant also called the stiffness constant of a spring is the value of force required for the deformation of the spring by a unit length.

Mathematically given as:

k=\frac{F}{\delta x}

where:

k= stiffness constant

F= force on the spring

\delta x= change in length of the spring

It is given in the question that spring 1 is easily compressible and requires less force to compress as compared to spring 2 and hence it has lesser stiffness constant than that of spring 2.

3 0
3 years ago
Other questions:
  • A real heat engine operates between temperatures tc and th. during a certain time, an amount qc of heat is released to the cold
    5·1 answer
  • What is the equation that defines work
    10·1 answer
  • Shah did not trust the results of an experiment that she had read about, so she is conducting the experiment herself. She goes t
    12·2 answers
  • What is the potential energy of two charges of +4.6 μC and +1.0 μC that are separated by a distance of 10.0 cm?
    12·1 answer
  • Help!!
    6·1 answer
  • A a healthy diet and exercise have an impact on the overall health of
    12·1 answer
  • 5. A 2000 kg truck has a momentum of 90,000 kg m/s. What is the velocity of the<br> truck?
    5·1 answer
  • suppose a 51 kg bungee jumper steps off the royal gorge bridge, in colorado. The bridge is situated 321 m above the arkansas riv
    10·1 answer
  • A cylinder-piston system contains an ideal gas at a pressure of 1.5 105 pa.
    9·1 answer
  • A girl holds an arrow in her hands, ready to shoot the arrow at a dragon who is just outside her arrow’s range of 45 meters. The
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!