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Answer:
By a factor of 1/4.
Explanation:
The impulse force that applies to an object undergoing rapid deceleration just before coming to a stop on the ground is given by the following formula,
in which
,
represent the change in momentum and the time taken for that change.
If one increases the time that is taken for the momentum change (which remains constant for this situation) by a factor 4 and if that new force is represented by
, the following manipulation confirms the answer to this question.
![\begin{aligned}\\\small F_1 &=\small \frac{\Delta (mV)}{4\Delta t}\\\\&=\small \frac{1}{4}\times\bigg[\frac{\Delta (mV)}{\Delta t}\bigg]\\\\&=\small \frac{1}{4}F\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%5C%5C%5Csmall%20F_1%20%26%3D%5Csmall%20%5Cfrac%7B%5CDelta%20%28mV%29%7D%7B4%5CDelta%20t%7D%5C%5C%5C%5C%26%3D%5Csmall%20%5Cfrac%7B1%7D%7B4%7D%5Ctimes%5Cbigg%5B%5Cfrac%7B%5CDelta%20%28mV%29%7D%7B%5CDelta%20t%7D%5Cbigg%5D%5C%5C%5C%5C%26%3D%5Csmall%20%5Cfrac%7B1%7D%7B4%7DF%5Cend%7Baligned%7D)
Here
is the force that was applied to the object previously.
#SPJ4
So what u do is 2112393921010
Answer:
8.87 gallons of kerosene
Explanation:
Step 1: Given and required data
- Energy to travel by plane per passenger trip: 1,260 MJ/passenger trip
- Energy per gallon of kerosene: 142 MJ/gal
Step 2: Calculate how many gallons of kerosene it takes to make the trip by plane
We can calculate the amount of kerosene required by combining the factor provided in Step 1.
1 gal/142 MJ × 1,260 MJ/passenger trip = 8.87 gal/passenger trip
8.87 gallons of kerosene are required to make the trip by plane.