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Ivan
3 years ago
7

A patio is in the shape of a trapezoid. The length of the longer base is 17 feet. The length of the shorter base is two feet les

s than half the longer base. The height is 4 feet. What is the area of the patio?

Mathematics
1 answer:
erma4kov [3.2K]3 years ago
5 0

Answer:

The area of the patio is 43 square feet

Step-by-step explanation:

In this question, we have a trapezoid and we are asked to calculate the area of the patio which is in the form of the trapezoid.

Please check attachment for possible trapezoid picture.

Mathematically, the area of the trapezoid can be calculated using the mathematical formula below;

A = 1/2 (a+b) h

where a and b are the lengths of the parallel sides.

Now, let’s say a is 17 feet

b was stated explicitly to be 2 feet half the length of the longer base. That would be 1/2(17) - 2 = 8.5 -2 = 6.5 feet

Now let’s calculate the area of the patio;

A = 1/2(6.5+17) * 4 = 2(23.5) = 47 square feet

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Which table represents the graph of a logarithmic function in the form y=log3x when b>1?
alex41 [277]

Answer:

<u><em>The satisfied table of the given function</em></u>y = log_{b} (x)<u><em></em></u>

<em>x                    1/8            1/4             1/2              1             2</em>

<em>y                    -3                 -2            -1               0               1</em>

<em></em>

Step-by-step explanation:

<u><em>Explanation</em></u> :-

Given logarithmic function y = log_{b} (x)   if b >1

Given first table

i)

put x = \frac{1}{8}     given b > 1 so we can choose b = 2

y = log_{2} (\frac{1}{8} )

y = log_{2} (2^{-3}  )

we will apply logarithmic formula

log x ⁿ = n log (x)

y = log_{2} (2^{-3}  ) = -3 log_{2} (2) = -3 (1) = -3

<em>y = -3</em>

<em>ii)</em>

<em>put x = </em>\frac{1}{4}<em>     given b > 1 so we can choose b = 2</em>

<em></em>y = log_{2} (\frac{1}{4} )<em></em>

<em></em>y = log_{2} (2^{-2}  )<em></em>

we will apply logarithmic formula

log x ⁿ = n log (x)

y = log_{2} (2^{-2}  ) = -2 log_{2} (2) = -2 (1) = -2

<em>y = -2</em>

<em>iii) </em>

<em>put x = </em>\frac{1}{2}<em>     given b > 1 so we can choose b = 2</em>

<em></em>y = log_{2} (\frac{1}{2} )<em></em>

y = log_{2} (2^{-1}  )

<em>we will apply logarithmic formula </em>

<em>log x ⁿ = n log (x)</em>

y = log_{2} (2^{-1}  ) = -1 log_{2} (2) = - (1) = -1

<em>y = -1</em>

<em>iv) </em>

<em>put x = 1     given b > 1 so we can choose b = 2</em>

<em></em>y = log_{2} (1 )<em> = 0</em>

<em>y = 0</em>

<em>v) </em>

<em>put x = </em>2<em>     given b > 1 so we can choose b = 2</em>

y = log_{2} (2 )

<em>y = 1</em>

<em></em>

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<em>y                    -3                 -2            -1               0               1</em>

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Step-by-step explanation:

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