*see attachment for diagram
Answer:
Perimeter = 38
Step-by-step explanation:
Recall: when two tangents are drawn to meet at a point outside a circle, the segments of the two tangents are congruent.
Given,
CQ = 5
PQ = 10
PR = 14
Perimeter of ∆PQR = RC + CQ + QB + BP + PA + AR
CQ = QB = 5 (tangents drawn from an external point)
BP = PQ - QB
BP = 10 - 5 = 5
BP = PA = 5 (tangents drawn from an external point)
AR = PR - PA
AR = 14 - 5 = 9
AR = RC = 9 (tangents drawn from an external point)
✔️Perimeter of ∆PQR = RC + CQ + QB + BP + PA + AR
= 9 + 5 + 5 + 5 + 5 + 9
Perimeter = 38
Answer:
- 3log(10) -2log(5) ≈ 1.60206
- no; rules of logs apply to any base. ln(x) ≈ 2.302585×log(x)
- no; the given "property" is nonsense
Step-by-step explanation:
<h3>1.</h3>
The given expression expression can be simplified to ...
3log(10) -2log(5) = log(10^3) -log(5^2) = log(1000) -log(25)
= log(1000/25) = log(40) . . . . ≠ log(5)
≈ 1.60206
Or, it can be evaluated directly:
= 3(1) -2(0.69897) = 3 -1.39794
= 1.60206
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<h3>2.</h3>
The properties of logarithms apply to logarithms of any base. Natural logs and common logs are related by the change of base formula ...
ln(x) = log(x)/log(e) ≈ 2.302585·log(x)
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<h3>3.</h3>
The given "property" is nonsense. There is no simplification for the product of logs of the same base. There is no expansion for the log of a sum. The formula for the log of a power does apply:
Numerical evaluation of Mr. Kim's expression would prove him wrong.
log(3)log(4) = (0.47712)(0.60206) = 0.28726
log(7) = 0.84510
0.28726 ≠ 0.84510
log(3)log(4) ≠ log(7)
Since f(x) = 2x - 1, all you need is to replace x with (a+h)
So f(a+h) = 2(a+h) - 1 = 2a + 2h - 1
Answer is D
Answer:
Step-by-step explanation:
- <em>Percent change is the difference in numbers divided by initial number converted to percent value.</em>
<u>Percent increase:</u>
<u>Percent decrease:</u>
- (70 - 50)/70*100% = 28.57%
<u>Compare:</u>
