All categories

2 years ago

14 POINTS

Chemistry

2 answers:

deff fn [24]2 years ago

4 0

Hydrochloric acid is created

Stella [2.4K]2 years ago

3 0

Answer:

The product of this reaction is the hydrochloric acid

Explanation:

The compounds required to perform a reaction are the reactants, in this case there are two: hydrogen and chlorine.

The resultant compound is denominated the product. In this case, the hydrochloric acid.

The reaction is:

$Cl_2 + H_2 \longrightarrow 2 HCl$

You might be interested in

The volume (in L) that would be occupied by 5.00 mols of 02 at STP is

crimeas [40]

Answer : The volume of oxygen at STP is 112.0665 L

Solution : Given,

The number of moles of $O_2$ = 5 moles

At STP, the temperature is 273 K and pressure is 1 atm.

Using ideal gas law equation :

$PV=nRT$

where,

P = pressure of gas

V = volume of gas

n = the number of moles

T = temperature of gas

R = gas constant = 0.0821 L atm/mole K (Given)

By rearranging the above ideal gas law equation, we get

$V=\frac{nRT}{P}$

Now put all the given values in this expression, we get the value of volume.

$V=\frac{(5moles)\times (0.0821Latm/moleK)\times (273K)}{1atm}=112.0665L$

Therefore, the volume of oxygen at STP is 112.0665 L

3 0

2 years ago

Write the overall, balanced molecular equation and indicate which element is oxidized and which is reduced for the following rea

galina1969 [7]

Answer:

Cd(s) + AgNO₃(aq) → Cd(NO₃)₂ (aq) + Ag(s)

Oxidized: Cd

Reduced: Ag

Explanation:

Cd(s) + AgNO₃(aq) → Cd(NO₃)₂ (aq) + Ag(s)

Cd → Cd²⁺ + 2e⁻ Half reaction oxidation

1e⁻ + Ag⁺ → Ag Half reaction reduction

Ag changed oxidation number from +1 to 0

Cd changed oxidation number from 0 to +2

Let's ballance the electrons

( Cd → Cd²⁺ + 2e⁻ ) .1

( 1e⁻ + Ag⁺ → Ag ) .2

Cd + 2e⁻ + 2Ag⁺ → 2Ag + Cd²⁺ + 2e⁻

Finally the ballance equation is:

Cd(s) + 2AgNO₃(aq) → Cd(NO₃)₂ (aq) + 2Ag(s)

4 0

3 years ago

DATA:

WITCHER [35]

Answer:

Explanation:

trial 1

5 0

2 years ago

At the start of a reaction, there are 0.0249 mol N2,

gladu [14]

Answer:

Explanation:

The reaction is given as:

$N_{2(g)} + 3H_{2(g)} \to 2NH_{3(g)}$

The reaction quotient is:

$Q_C = \dfrac{[NH_3]^2}{[N_2][H_2]^3}$

From the given information:

TO find each entity in the reaction quotient, we have:

$[NH_3] = \dfrac{6.42 \times 10^{-4}}{3.5}\\ \\ NH_3 = 1.834 \times 10^{-4}$

$[N_2] = \dfrac{0.024 }{3.5}$

$[N_2] = 0.006857$

$[H_2] =\dfrac{3.21 \times 10^{-2}}{3.5}$

$[H_2] = 9.17 \times 10^{-3}$

∴

$Q_c= \dfrac{(1.834 \times 10^{-4})^2}{(0.0711)\times (9.17\times 10^{-3})^3} \\ \\ Q_c = 0.6135$

However; given that:

$K_c = 1.2$

By relating $Q_c \ \ and \ \ K_c$ , we will realize that $Q_c \ \ < \ \ K_c$

The reaction is said that it is not at equilibrium and for it to be at equilibrium, then the reaction needs to proceed in the forward direction.

7 0

2 years ago

HELP................!!!!

expeople1 [14]

Your answer is 1-3-2-4 , grass sand water rock

3 0

3 years ago