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Gala2k [10]
3 years ago
10

GEOMETRY- What is the area of the figure, show your work please!

Mathematics
1 answer:
Kamila [148]3 years ago
8 0
Since this is a 45-45-90 right triangle, the hypotenuse = sqrt2 * leg
24 is the hypotenuse so we need to find the leg.
24 = sqrt2 * leg
Divide both sides by sqrt2
leg = 16.97
A = (1/2)b*h
A = (1/2)*16.97*16.97
A = 144ft^2
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If f(x) = 4x2 and g(x) = x+1, find (f•g)(x)
slamgirl [31]

Answer:

4x^3+4x^2

Step-by-step explanation:

f(x) = 4x^2

g(x) = x+1

(f•g)(x) = (4x^2) *(x+1) = 4x^3+4x^2

7 0
3 years ago
(8x-17)(5x+19)<br> Find the converse and x
pychu [463]

(8x-17)(5x+19)\\40x^{2}+152x-85x-323\\ 40x^{2}+67x-323

4 0
2 years ago
Question 1
Viktor [21]

Answer:

a. -3x = -2y

When x=6, y=9

Step-by-step explanation:

From the hanger, There are two sides

If x=triangle and y=square

First side has 1 triangle and 3 squares

It can be represented by

x+3y

Second side has 4 triangles and 1 square

It can be represented by

4x+y

Equate the first and second side

x+3y=4x+y

Collect like terms

x+3y-4x-y=0

-3x+2y=0

-3x=-2y

Find y when x=6

-3(6)=-2y

-18=-2y

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7 0
3 years ago
Plz Help... I am very stupid ​
Elan Coil [88]

Answer:

b

Step-by-step explanation:

It's b because if you plug in 1 for d in each of the equations, you get 99 in b only.

5 0
2 years ago
Read 2 more answers
What are the solutions of 3x2 + 14x + 16 = 0?
Leya [2.2K]

Answer:

Given the equation: 3x^2+14x+16=0

The general equation of quadratic formula for ax^2+bx+c=0 where a, b and c are constant;

then, the solution for this equation  is given by;

&#10;x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}              ......[1]

From the equation, 3x^2+14x+16=0 we have

a =2, b=14 and c=16

Substitute these values in [1] to solve for x;

&#10;x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{-14\pm\sqrt{(14)^2-4(3)(16)}}{2(3)}              

or

x=\frac{-14\pm\sqrt{196-192}}{6} =\frac{-14\pm\sqrt{4}}{6}

Simplify:

x=\frac{-14\pm\sqrt{4}}{6} =\frac{-14\pm 2}{6}

then,

x=\frac{-14+2}{6} =\frac{-12}{6} =-2 and

x=\frac{-14-2}{6} =\frac{-16}{6} =\frac{-8}{3}

Therefore, the solutions for the given equation is; x =-2 and x =-\frac{8}{3}



6 0
3 years ago
Read 2 more answers
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