Answer:
2. + 2.1
Explanation:
Formula for resistance is as follows
R_t = R₀ ( 1 + α t )
R_t is resistance at changed temperature , Ro is resistance at initial temperature , α is temperature coefficient of resistivity . t is temperature change .
For iron , R₀ = 10 , α = 5 x 10⁻³ , t = - 100 degree
R_t = 10( 1 + 5 x 10⁻³ x - 100 )
= 10( 1 - 5 x 10⁻³ x 100 )
10 x ( 1 - .5 )
10 x .5
For carbon
, R₀ = 10 , α = - 0.5 x 10⁻³ , t = - 100 degree
R_t = 10( 1 - 0. 5 x 10⁻³ x - 100 )
= 10( 1 + .5 x 10⁻³ x 100 )
10 x ( 1 + .05 )
10 x 1.05
Required ratio
= 10 x 1.05 / 10 x .5
= 105 / 50
= 21 / 10
= 2.1
Explanation:
Explanation:
Y = 5 Sin27(.2x-3t)
= 5 Sin(5.4x - 81 t)
Amplitude = 5 m
Angular frequency w = 81
frequency = w/ 2π = 81/(2 x 3.14)
-12.89
Wave length λ = 2π/ k,
k = 5.4
λ = 2π/ 5.4
= 1.163 m
Phase velocity=w / k
= 81/5.4
15 m/s.
The wave is travelling in + ve x - direction.
hope help
Explanation:
The X-component of the velocity = Vcosx. Where, V = magnitude of the velocity. The x component of velocity will depend on the diagram. It the angle is measured from the x-axis which is considered the horizontal then Vx = Vcos(theta). The magnitudes of the components of velocity v → are v x = v cos θ and v y = v sin θ , v x = v cos θ and v y = v sin θ , where v is the magnitude of the velocity and θ is its direction relative to the horizontal, as shown in Figure 4.12. Derivation of the Trajectory Formula.
y = refers to the vertical position of the object in meters. x = refers to the horizontal position of the object in meters. Horizontal velocity component: Vx = V * cos(α)
Vertical velocity component: Vy = V * sin(α)
Time of flight: t = [Vy + √(Vy² + 2 * g * h)] / g.
Range of the projectile: R = Vx * [Vy + √(Vy² + 2 * g * h)] / g.
Maximum height: hmax = h + Vy² / (2 * g)
Answer:
I would say the answer is the wave of 21.000Hz
Explanation:
Because it has more frequency, and as more frequency you add, the time or longer period also increases.
As water vapour cools, it changes back into liquid form. drops come together to form 'clouds'? maybe
