Answer:
can be there and we will make sure to get a me to do it and get it done by then and I'll let u get back with you are you are going for the best way of doing it for a while now that I am a.
Answer:
2.866 x 10^8 J
Explanation:
Thermal conductivity, K = 0.040 W/m^2 k
Area of the wall, A = 470 m^2
Thickness, d = 17 cm = 0.17 m
difference in temperature, ΔT = 30° C
The rate of heat flow is H.
Time, t = 1 day = 1 x 24 x 60 x 60 second = 86400 second
By use of formula of heat flow


H = 2.866 x 10^8 J
Answer:
<em>The thermal energy dissipated in A would be twice that in B</em>
Explanation:
Resistor B (RB)= R
Resistor A (RA)= 2 R
When they are connected in series the equivalent Resistance in the circuit would be;
Equivalent resistance = RA +RB = R + 2 R = 3 R;
From ohms law I = V/R
I = V/3 R
Now the thermal energy is the power dissipated by the circuit and can be obtained thus;
P =
Then,

Therefore Pa : Pb = 2: 1, this means that the thermal energy dissipated in A would be twice that in B