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emmainna [20.7K]
4 years ago
15

Two Forces Of Magnitude 20N Each Are Acting At 30 And 60 degree with xAxis the Y Component Of The Resultant Force Is

Physics
1 answer:
vodka [1.7K]4 years ago
5 0

We can find the y-component of the resultant force by adding the y-components of the two 20N forces.

For a force of magnitude F and lying at an angle off the x-axis θ, the y-component of the force is given by:

Fsin(θ)

The magnitude of the two forces is 20N, and they lie at 30° and 60°, so the sum of their y-components, and therefore the y-component of the resultant force, is:

20sin(30°)+20sin(60°)

= 27.3N

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Why is the following situation impossible? Two identical dust particles of mass 1.00 µg are floating in empty space, far from an
Igoryamba

Answer:

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Yellow light of wavelength 590 nm passes through a diffraction grating and makes an interference pattern on a screen 80 cm away.
riadik2000 [5.3K]

Answer:B

Explanation:

Given

Wavelength of light \lambda =590\ nm

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d=\frac{m\lambda }{\sin \theta _m}-----1

Position of bright fringe is given by

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\theta _m=\tan^{-1}(\frac{y}{L})

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d=\frac{m\lambda }{\sin (\tan^{-1}(\frac{y}{L}))}

Therefore N=d^{-1}

N=\frac{\sin (\tan^{-1}(\frac{y}{L}))}{m\lambda }

for m=1

N=\frac{\sin (\tan^{-1}(\frac{1.9\times 10^{-2}}{0.8}))}{1\times 590\times 10^{-9}}

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N=40\ line/mm

   

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