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tiny-mole [99]
3 years ago
5

Write the product of 6x-4 and the multiplicative inverse of 1 over 5

Mathematics
1 answer:
nlexa [21]3 years ago
6 0

Answer:

  30x -20

Step-by-step explanation:

The multiplicative inverse (reciprocal) of 1/5 is 5/1 = 5. Multiplying that by 6x-4 gives ...

  5 × (6x -4) = 30x -20

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The box plot below represents some data set. What is the interquartile range (IQR) of
vesna_86 [32]

Answer:

I think the IQR is 100

Step-by-step explanation:

You would have to find the first and third quartiles first. After that you would subtract the third quartile by the first to get the IQR

6 0
3 years ago
The net represents a toy box that has the shape of a rectangular prism. Each unit on the coordinate plane represents 1 meter. If
8090 [49]

Answer:

B) 4

Step-by-step explanation:

(2*4)+(2*1)=10 So, 10/2=2 but both sides 4

8 0
3 years ago
Given that the average rate of change for y = f(x) over the interval [0,3] is −1, the average rate of change over the interval [
Svet_ta [14]

Answer:

Answer is 2

Step-by-step explanation:

We know that average rate of change of a function f(x) in the interval (a,b) is

\frac{1}{b-a} \int\limits^a_b {f(x)} \, dx

Using this we can say that

\int\limits^0_3 {f(x)} \, dx =-1(3)=-3\\\int\limits^2_3 {f(x)} \, dx =5(1)=5\\\\\int\limits^2_6 {f(x)} \, dx =4(5)=20\\

Using properties of integration we have

3 to 6 integral = 20-5 =15

0 to2 integral = -3=5 =-8

Thus integral form 0 to 6 would be = -8+15+5 = 12

Average rate of change form 0 to 6 = \frac{12}{6} =2

Answer is 2

7 0
3 years ago
Solve 2x - 9 - 7x = 11. A. -4 B. -1/4 C.2/5 D. 4
HACTEHA [7]
A. -4

-5x divided by 20 = -4
4 0
3 years ago
Read 2 more answers
What is the approximate length of the diagonal of a square with side length of 20 centimeters
zhuklara [117]
Answer:28.28 cm

Explanation:

a² + b² = c²

20² + 20² = c²

c² = 400 + 400

c² = 800

c = √800

c = 28.28 cm
5 0
4 years ago
Read 2 more answers
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